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3 years ago

If the [A-]/[HA] ratio of a base/weak acid mixture changes from 10/1 to 1/10, how much does the pH change:

Chemistry

1 answer:

andreev551 [17]3 years ago

3 0

Answer:

The pH changes by 2.0 if the [A-]/[HA] ratio of a base/weak acid mixture changes from 10/1 to 1/10.

Explanation:

To solve this problem we use the Henderson-Hasselbach equation:

pH = pKa + log [A⁻]/[HA]

Let's say we have a weak acid whose pKa is 7.0:

pH = 7.0 + log [A⁻]/[HA]

If the [A⁻]/[HA] ratio is 10/1, we're left with:

pH = 7.0 + log (10/1)

pH = 7.0 + 1

pH = 8.0

Now if the ratio is 1/10:

pH = 7.0 + log (1/10)

pH = 7.0 - 1

pH = 6.0

The difference in pH from one case to the other is (8.0-6.0) 2.0.

So the pH changes by 2.0 if the [A-]/[HA] ratio of a base/weak acid mixture changes from 10/1 to 1/10.

Keep in mind that no matter the value of pKa, the answer to this question will be the same.

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3 years ago

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39.0 % = ethylene glycol

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imagine the total mass = 100g

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