Answer:
Explanation:
4FeS₂ + 11O₂ → 2Fe₂O₃ + 8SO₂.
4 moles of FeS₂ reacts with 11 moles of O₂
8 moles of FeS₂ reacts with 22 moles of O₂
Moles of O₂ available is 15 .
So O₂ is in short supply .
So O₂ is the limiting reagent.
Option (c) is the right choice.
Answer:
Explanation:
Cubic decimeter is the same unit as liter; so, mole per cubic decimeter is mole per liter, and that is the unit of concentration of molarity. Thus, what is asked is the molarity of the solution. This is how you find it.
1. <u>Take a basis</u>: 1 dm³ = 1 liter = 1,000 ml
2. <u>Calculate the mass of 1 lite</u>r (1,000 ml) of solution:
- density = mass / volume ⇒ mass = density × volume
Here, the density is given through the specific gravity
Scpecific gravity = density of acid / density of water
Take density of water as 1.00 g/ml.
- density of solution = 1.25 g/ml
- mass solution = 1.25 g/ml × 1,000 ml = 1,250 g
3. <u>Calculate the mass of solute</u> (pure acid)
- % m/m = (mass of solute / mass of solution) × 100
- 56 = mass of solute / 1,250 g × 100
- mass of solute = 56 × 1,250g / 100 = 700 g
4. <u>Calculate the number of moles of solute</u>:
- moles = mass in grams / molar mass = 700 g / 70 g/mol = 10 mol
5. <u>Calculate molarity (mol / dm³)</u>
- M = number of moles of solute / liter of solution = 10 mol / 1 liter = 10 mol/liter.
Answer:
The answer to your question is 3.5 moles of H₂
Explanation:
Data
moles of H₂ = ?
moles of Zn = 3.5 moles
moles of HCl = excess
Process
1.- Write the balanced chemical reaction
Zn + 2HCl ⇒ ZnCl₂ + H₂
Reactants Elements Products
1 Zn 1
2 Cl 2
2 H 2
2.- Use the coefficients of the balanced reaction to calculate the moles of H₂
1 mol of Zn ----------------- 1 mol of H₂
3.5 moles of Zn ------------- x
x = (3.5 x 1)/1
x = 3.5 moles of H₂
Answer:
1. aa
2. They have similar DNA
Explanation:
1. According to the question 1, wrinkled seeds (A) are dominant over round seeds (a) in pea plants. This means that, based on the law of dominance proposed by Mendel, wrinkled seeds will be expressed over round seeds in a heterozygous state (Aa).
However, since the round seed phenotype is a recessive trait, it will only be expressed when the alleles for round seeds (a) are the same in the gene i.e. aa genotype.
2. Based on the information in question 2, Ricky, who is working on a family tree for his school project, realizes that his close relatives all look similar in the pictures he collected. This is possible because of the SIMILARITY OF THEIR DNA (genetic material). Note that, relatives are connected by the genes that are inherited from one another, hence, they possess a similar DNA, which is the most valid reason for the resemblance.
Through the vibration of particles in a medium.