Question

How many mL of 0.25 M NaOH would have 0.18 moles of NaOH

Answer 1

Answer:

$720\ \text{mL}$

Explanation:

M = Molarity of NaOH = 0.25 M = 0.25 mol/L

n = Number of moles of NaOH = 0.18 moles

Volume of solution is given by

$V=\dfrac{n}{M}$

$\Rightarrow V=\dfrac{0.18}{0.25}$

$\Rightarrow V=0.72\ \text{L}\times 10^3=720\ \text{mL}$

The volume of NaOH in the solution is $720\ \text{mL}$.