Answer:
Protons are composite particles composed of three valence quarks: two up quarks of charge + 23e and one down quark of charge − 13e. The rest masses of quarks contribute only about 1% of a proton's mass.
<u><em>Composition:</em></u> 2 up quarks (u), 1 down quark (d)
<u><em>Magnetic moment:</em></u> 1.41060679736(60)×10−26
<u><em>Discovered:</em></u> Observed as H+ by Eugen Goldst.
Explanation:
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Answer:
B and D
Explanation:
Because its adaptions they need to survive in the cold.
Answer:
the final result is:oxygen-244g and hydrogen-111g
Answer:
79.74*10^6 Pa
Explanation:
Based on the parameters provided, we have:
ε = ln()
Where initial gauge length = 3 cm and the final gauge length is 3.5 cm. Therefore:
ε = ln(3.5/3) = ln(1.167) = 0.154
Similarly,
σ = F/[3.142*(di^2)/4]
Where σ = 120*10^6 Pa and di = 1 cm = 0.01 m
Therefore,
F = 120*10^6 * 3.142*(0.01^2)/4 = 9426 N
σ = F/[3.142*(df^2)/4 = 9426/[3.142*(0.00926^2)/4 = 9426/6.74*10^-5 = 139.95*10^6 Pa
σ = k*ε = 139.95*10^6
k = 139.95*10^6/(0.154)^0.5 = 356.63*10^6 Pa
Therefore, when ε = 0.05 cm/cm
σ = 356.63*10^6 (0.05)^0.5 = 79.74*10^6 Pa