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Firlakuza [10]
3 years ago
5

Deduct for thousand eleven hundred and a half from twelve thousand twelve hundred and twelve​

Mathematics
1 answer:
Mama L [17]3 years ago
5 0

Answer:

8111.5

Step-by-step explanation:

Deduct for thousand eleven hundred and a half from twelve thousand twelve hundred and twelve

Rewriting the above question in figure :

4000 + 100 + 0.5 = 5100.5

12000 + 1200 + 12 = 13212

13212 - 5100.5 = 8111.5

= 8111.5

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Ksivusya [100]
<span>x = child ticket price
y = adult ticket price 
5x+3y=52 the cost accounting for the first group.
3x+2y=38 the cost accounting for the second group.

Child price: 5$
Adult price: 9$</span>
3 0
3 years ago
How do i find joint relative frequency?
Svet_ta [14]
A joint relative frequency is found by dividing a frequency that is not in the Total row or the Total column by the frequency’s row total or column total.
3 0
3 years ago
In the past, the average age of employees of a large corporation has been 40 years. Recently, the company has been hiring older
Viktor [21]

Answer:

p_v =P(t_{(63)}>2.5)=0.0075  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the mean age is significantly higher than 45 years at 5% of significance.  

Step-by-step explanation:

1) Data given and notation  

\bar X=45 represent the mean height for the sample  

s=16 represent the sample standard deviation for the sample  

n=64 sample size  

\mu_o =40 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean age is higher than 40 years, the system of hypothesis would be:  

Null hypothesis:\mu \leq 40  

Alternative hypothesis:\mu > 40  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{45-40}{\frac{16}{\sqrt{64}}}=2.5    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=64-1=63  

Since is a one right tailed test the p value would be:  

p_v =P(t_{(63)}>2.5)=0.0075  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the mean age is significantly higher than 45 years at 5% of significance.  

6 0
3 years ago
4x + 1 = 5, find x assuming x is a whole number​
levacccp [35]

Answer:

x=1

Step-by-step explanation:

4x+1=5

4x=5-1

4x=4

x=4/4=1

This happens to be a whole number.

4 0
3 years ago
Of the students in Rosalie's dance class, 29 out of 59 have participated in dance class before. About how many of her students h
Harrizon [31]

Answer:

B

Step-by-step explanation:

half of 59 is 29.5, which is very close to 29. this indicates that this fraction (29/59) is the closest to one half, which is answer choice B.

5 0
2 years ago
Read 2 more answers
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