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Firlakuza [10]
3 years ago
5

Deduct for thousand eleven hundred and a half from twelve thousand twelve hundred and twelve​

Mathematics
1 answer:
Mama L [17]3 years ago
5 0

Answer:

8111.5

Step-by-step explanation:

Deduct for thousand eleven hundred and a half from twelve thousand twelve hundred and twelve

Rewriting the above question in figure :

4000 + 100 + 0.5 = 5100.5

12000 + 1200 + 12 = 13212

13212 - 5100.5 = 8111.5

= 8111.5

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An animal reserve has 40,000 elk. The population increases 11% a year. How long tell the population is equal to 80,000. If someo
sukhopar [10]

Answer:

7 years (This answer is to the nearest year)

Step-by-step explanation:

The way you could work this out is by trial and error. 11 % a year means that its population increases by 4400 annually. 40,000 X 1.11^1 gives you the amount it would be after one year (44000). I got the 1.11 because of the percentage (0.11) plus the amount you need to do percentage increase (1). Then all you do is keep on going up till you hit the number you need (80,000) after about 7 years the total would have hit 80,000 and would have actually went past it (83046)

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3 years ago
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barxatty [35]

\frac{ { - 5}^{2}  +  {10}^{2} }{(2 \times ( - 5) \times 3) +  {3}^{3} } =  \frac{ - 25 + 100}{ - 30 + 27}   =  \\  =  \frac{75}{ - 3}  =  - 25

5 0
3 years ago
Read 2 more answers
Max and Sasha exercise a total of 20 hours each week. Max exercises 15 hours less than 4 times the
navik [9.2K]

Answer:

Max exercises 13 hours a week, and Sasha 7.

Step-by-step explanation:

To find the number of hours each of them exercises during the week, we solve the system of equations.

In the second equation:

x = 4y - 15

Replacing in the first equation:

x + y = 20

4y - 15 + y = 20

5y = 35

y = \frac{35}{5}

y = 7

So Sasha exercises 7 hours per week.

Max:

x + y = 20

x + 7 = 20

x = 13

Max exercises 13 hours a week.

6 0
3 years ago
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2 years ago
Triangle $ABC$ has a right angle at $B$. Legs $\overline{AB}$ and $\overline{CB}$ are extended past point $B$ to points $D$ and
Lisa [10]

Answer:

Given :

ABC is a right triangle in which ∠ABC = 90°,

Also, Legs AB and CB are extended past point B to points D and E,

Such that,

\angle EAC = \angle ACD = 90^{\circ}

To prove :

EB\times BD=AB\times BC

Proof :

In triangles AEC and EBA,

∠EAC= ∠ABE ( right angles )

∠CEA = ∠AEB ( common angles )

By AA similarity postulate,

\triangle AEC \sim \triangle EBA,

Similarly,

\triangle AEC \sim \triangle ABC

\implies\triangle EBA\sim \triangle ABC-----(1)

Now, In triangles ADC and CBD,

∠ACD = ∠CBD ( right angles )

∠ADC= ∠BDC ( common angles )

By AA similarity postulate,

\triangle ADC \sim \triangle CBD,

Similarly,

\triangle ADC \sim \triangle ABC

\implies \triangle CBD\sim \triangle ABC-----(2)

From equations (1) and (2),

\triangle EBA\sim \triangle CBD

The corresponding sides of similar triangles are in same proportion,

\frac{EB}{BC}=\frac{AB}{BD}

\implies EB\times BD=AB\times BC

Hence, proved....

5 0
3 years ago
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