Answer:
121.78 g
Explanation:
You multiply the mols by the grams in one mol.
Answer:
A. 0.1 M
Explanation:
Given data
- Mass of NaI (solute): 15 g
- Molar mass of NaI: 150 g/mol
Step 1: Calculate the moles of solute
Step 2: Calculate the molarity of the solution
The molarity of the solution is equal to the moles of solute divided by the liters of solution.
The solution is 0.1 M.
Answer:
the ratio would be 1:2:1
Explanation:
since it is C6 H12 O6
12 is double of 6 so it would be 2
and 6 is considered 1
I would have to say D) carbon-to-hydrogen ratio
Answer:
1 M
Explanation:
The molarity of a solution, M, is a measure of the concentration of that solution and it refers to the number of moles of solute (mol) per liter (L) of solution. The molarity (M) can be calculated using the formula:
M = number of moles (n) /volume (V)
In this question, a 500 ml aqueous solution of Na3PO4 was prepared using 82g of the solute.
Molar mass of Na3PO4 = 23(3) + 15 + 16(4)
= 69 + 31 + 64
= 164g/mol
Mole = mass/molar mass
mole = 82/164
mole = 0.5 mol
Volume in Litres (L) = 500 ml ÷ 1000 = 0.500L
Therefore, Molarity (M) = 0.5/0.500
Molarity = 1 M or 1 mol/L
