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Molodets [167]
4 years ago
9

What is the amount of ca3(po4)2 that can be prepared from a mixture of 9g of Ca(OH) 2 and 11g of H3po4?

Chemistry
1 answer:
schepotkina [342]4 years ago
6 0
Moles Ca(OH)2 = 12.9 /74.092 g/mol=0.174 
<span>moles H3PO4 = 18.37/98.0 g/mol=0.187 </span>
<span>3 : 2 = x : 0.187 </span>
<span>x = moles Ca(OH)2 needed =0.281 </span>
<span>we have only 0.174 moles of calcium hydroxide so it is the limiting reactant </span>
<span>moles Ca3(PO4)2 = 0.174/3=0.0580 </span>
<span>mass = 0.0580 mol x 310.18 g/mol=18.0 g</span>
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Lewis dot structure of PSI3 with minimized formal charges
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We need to know how many valence electrons are present in a given molecule in order to determine its Lewis dot structure.

<h3>What is Lewis dot structure?</h3>

Lewis dot structure is defined as the visual representation of atoms' electrons using a diagram. It describe the bonds that exist between a molecule's lone pairs of electrons and its atoms.

A lone pair of electrons on the atom with the formal charge of 1- can typically be converted into a bonding pair that is shared with the atom that has the formal charge of 1+ in order to reduce the formal charges when they are present.

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3 0
2 years ago
39. suppose an aqueous solution contains both table sugar and table salt. can you separate either of these solutes from the wate
Degger [83]

Answer:

No, assuming that the salt/sugar is already dissolved

Explanation:

As long as the particle size is too big, it won't filter through. Therefore, if it is dissolved, it will pass through the filter.

If you were to throw rocks in there or something, and they are non-dissolvable, then yes.

7 0
2 years ago
Which of the following is a heterogeneous mixture?
masya89 [10]
The answer would be c <span>a jar of mixed nuts.</span>
8 0
3 years ago
Read 2 more answers
How many moles of H2 are needed to react with 4.8 mol of O2 ?
VLD [36.1K]

Answer:

9.6 mol

Explanation:

Start by writing out the balanced equation of the reaction.

2H_{2} + O_{2} ⇒ 2H_{2}O

Here you will see 2 mol of hydrogen for every 1 mol of oxygen. Using this ratio, you can assume the amount of hydrogen will always be double that of oxygen. In this case, 4.8 * 2 = 9.6

5 0
2 years ago
Determine the resulting pH when 12mL if 0.16M HCl are reacted with 32 mL if 0.24M KOH.
TEA [102]

Answer:

pH = 13.1

Explanation:

Hello there!

In this case, according to the given information, we can set up the following equation:

HCl+KOH\rightarrow KCl+H_2O

Thus, since there is 1:1 mole ratio of HCl to KOH, we can find the reacting moles as follows:

n_{HCl}=0.012L*0.16mol/L=0.00192mol\\\\n_{KOH}=0.032L*0.24mol/L=0.00768mol

Thus, since there are less moles of HCl, we calculate the remaining moles of KOH as follows:

n_{KOH}=0.00768mol-0.00192mol=0.00576mol

And the resulting concentration of KOH and OH ions as this is a strong base:

[KOH]=[OH^-]=\frac{0.00576mol}{0.012L+0.032L}=0.131M

And the resulting pH is:

pH=14+log(0.131)\\\\pH=13.1

Regards!

3 0
3 years ago
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