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4 years ago

What is the amount of ca3(po4)2 that can be prepared from a mixture of 9g of Ca(OH) 2 and 11g of H3po4?

1 answer:

6 0

Moles Ca(OH)2 = 12.9 /74.092 g/mol=0.174
moles H3PO4 = 18.37/98.0 g/mol=0.187 
3 : 2 = x : 0.187 
x = moles Ca(OH)2 needed =0.281 
we have only 0.174 moles of calcium hydroxide so it is the limiting reactant 
moles Ca3(PO4)2 = 0.174/3=0.0580 
mass = 0.0580 mol x 310.18 g/mol=18.0 g

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What are the products in this chemical reaction? 2H3PO4+3Ca(OH)2→Ca3(PO4)2+6H2O

finlep [7]

<h2>Answer:C</h2>

Explanation:

A chemical equation is a equation that describes a corresponding chemical reaction.

A chemical reaction is generally written as

$reactants$ → $products$

$reactants$ refer to all the reactants involved in the chemical reaction.

Reactants are usually written on the left hand side of the chemical equation.

$products$ refer to all the products formed in the chemical reaction.

products are usually written on the right hand side of the chemical equation.

In the given reaction, $Ca_{3}(PO_{4})_{2}$ , $H_{2}O$ are written on the right side of the equation.

So, $Ca_{3}(PO_{4})_{2}$ , $H_{2}O$ are the products.

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masya89 [10]

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Answer: 43 L

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4 years ago

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sashaice [31]

Ephedrine, a central nervous system stimulant, is used in nasal sprays as a decongestant. This compound is a weak organic base:

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b) Calculate Kb for ephedrine.

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pH = 11,33.
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3 years ago

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dusya [7]

Answer:

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