Answer:
(3R,4R)-4-bromohexan-3-ol
Explanation:
In this case, we have reaction called <u>halohydrin formation</u>. This is a <u>markovnikov reaction</u> with <u>anti configuration</u>. Therefore the halogen in this case "Br" and the "OH" must have <u>different configurations</u>. Additionally, in this molecule both carbons have the <u>same substitution</u>, so the "OH" can go in any carbon.
Finally, in the product we will have <u>chiral carbons</u>, so we have to find the absolute configuration for each carbon. On carbon 3 we will have an "R" configuration on carbon 4 we will have also an "R" configuration. (See figure 1)
I hope it helps!
The energy needed to raise the temperature of 2.83 kg of the oil from 23 to 191 is calculated using Mc delta T formula
M= mass ( 2.83 Kg to grams = 2.83 x1000= 2830 grams)
C= specific heat capacity = 1.75 j/g/c
delta T= change in temperature = 191- 23 = 168 c
heat energy = 1.75 j/g/c x 2830 g x 168 c= 832020 J
Answer:
Tin(IV) Oxide + Carbon = Tin + Carbon Monoxide
Explanation:
Answer:
Car 3 with a net force of 12N
Explanation:
The formula is F=MA
Hope this helps friend
Ca: 40.078 g/mol
C: 12.011 g/mol
O: 16.00g/mol
CaCO3:
molar mass of 100.089g/mol