2 years ago

Determine the number of significant figures in 478 cm

Chemistry

1 answer:

Grace [21]2 years ago

3 0

Answer:

There are 3 significant figures on this one.

You might be interested in

Sulfuric acid dissolves and completely dissociates in water and a solvation sphere of water molecules forms around the ions. Thi

gizmo_the_mogwai [7]

The answer is D

Hope this help;)

3 0

3 years ago

Read 2 more answers

What is the mass of 3.8 × 1024 atoms of argon (Ar)?

gulaghasi [49]

40 g Ar.......6.023*10^23 atoms
x g Ar.......3.8*10^24 atoms
x=40*3.8*10^24/(6.023*10^23)=252,365g Ar

6 0

3 years ago

A solution has a pH of 2.5. What is its [OH-] ?

gulaghasi [49]

POH=14-pH=14-2.5=11.5 pH=-log[H+] 2.5=-log [H+] [H+]=10^-5/2 [OH-]=10^(14-5/2)=10^23/2

8 0

2 years ago

The equilibrium constant for the reaction

FinnZ [79.3K]

Answer: The concentrations of $Cl_2$ at equilibrium is 0.023 M

Explanation:

Moles of $Cl_2$ = $\frac{\text {given mass}}{\text {Molar mass}}=\frac{10g}{71g/mol}=0.14mol$

Volume of solution = 1 L

Initial concentration of $Cl_2$ = $\frac{0.14mol}{1L}=0.14M$

The given balanced equilibrium reaction is,

$COCl_2(g)\rightleftharpoons CO(g)+Cl_2(g)$

Initial conc. 0.14 M 0 M 0M

At eqm. conc. (0.14-x) M (x) M (x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[CO]\times [Cl_2]}{[COCl_2]}$

Now put all the given values in this expression, we get :

$4.63\times 10^{-3}=\frac{x)^2}{(0.14-x)}$

By solving the term 'x', we get :

x = 0.023 M

Thus, the concentrations of $Cl_2$ at equilibrium is 0.023 M

7 0

3 years ago

B) At what pH is H2 at 10 atm at equilibrium with this solution and pure nickel?

scZoUnD [109]

19372)19292
Hahaha ss
Qowieuww

6 0

3 years ago

Determine the number of significant figures in 478 cm​

Determine the number of significant figures in 478 cm