Answer:
The perimeter (to the nearest integer) is 9.
Step-by-step explanation:
The upper half of this figure is a triangle with height 3 and base 6. If we divide this vertically we get two congruent triangles of height 3 and base 3. Using the Pythagorean Theorem we find the length of the diagonal of one of these small triangles: (diagonal)^2 = 3^2 + 3^2, or (diagonal)^2 = 2*3^2.
Therefore the diagonal length is (diagonal) = 3√2, and thus the total length of the uppermost two sides of this figure is 6√2.
The lower half of the figure has the shape of a trapezoid. Its base is 4. Both to the left and to the right of the vertical centerline of this trapezoid is a triangle of base 1 and height 3; we need to find the length of the diagonal of one such triangle. Using the Pythagorean Theorem, we get
(diagonal)^2 = 1^2 + 3^2, or 1 + 9, or 10. Thus, the length of each diagonal is √10, and so two diagonals comes to 2√10.
Then the perimeter consists of the sum 2√10 + 4 + 6√2.
which, when done on a calculator, comes to 9.48. We must round this off to the nearest whole number, obtaining the final result 9.
Answer:
5 right and down 3 and (0 means the middle) so middle down 4
Step-by-step explanation:
lit : )
given the following sets.
A = {0, 1, 2, 3}
B = {a, b, c, d}
C = {0, a, 2, b}
Find B C.
Answer:
101.07ft^2
Step-by-step explanation:
Given data
radius= 5ft
h= 9ft
When the radius and height are both multiplied by 1/2
radius= 5/2ft = 2.5ft
height= 9/2 ft= 4.5ft
The expression for the surface area of the cone is
A=πr(r+√h^2+r^2)
Substiute
A= 3.142*2.5(2.5√4.5^2+2.5^2)
A= 7.855(2.5√20.25+6.25)
A= 7.855(2.5√26.5)
A= 7.855(2.5*5.147)
A=101.07 ft^2
Hence the surface area is 101.07ft^2
