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ad-work [718]
3 years ago
13

If an object is not moving, it has no

Chemistry
2 answers:
marishachu [46]3 years ago
7 0

Answer:

b

Explanation:

Tanzania [10]3 years ago
5 0

Answer:

that answer is B

Explanation:

the answer is b luv

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Boyle's law states that the pressure of a gas is always:
natka813 [3]

Answer:

d. inversely proportional to the volume of its container.

Explanation:

Boyle's law  states that at constant temperature and number of moles, the pressure of the gas is inversely proportional to the volume of the gas.

Thus, P ∝ T

P is the pressure

T is the temperature

For two gases at same temperature, the law can be written as:-

{P_1}\times {V_1}={P_2}\times {V_2}

<u>Thus, according to the question, the answer is:- d. inversely proportional to the volume of its container.</u>

7 0
3 years ago
Calculate the number of moles found in 3.045x1024 atoms of helium.<br><br> PLS HELP
Kisachek [45]

Explanation:

so for this u have to use this equation where

Moles = number of particle/6.02×10^23

= 3.045 × 10^24/6.02×10^23

= 5.0581

write it to 3 S.F so 5.06 moles

4 0
2 years ago
What is the balanced chemical equation for the reaction of potassium with sulfur?
Aneli [31]

K + S = K2S

Potassium reacts with sulfur to produce potassium sulfide

8 0
3 years ago
What is the minimum (non-zero) thickness of a benzene (n = 1.501) thin film that will result in constructive interference when v
ad-work [718]

Explanation:

At each reflecting surface (benzene and glass) there will be 180 degree phase change.

Now, for constructive interference the optical path in benzene is \lambda.

Formula to calculate thickness of a benzene thin film is as follows.

     Optical path length through benzene (\lambda) = 2 \times n \times d

Hence, substituting the given values into the above formula as follows.

    Optical path length through benzene = 2 \times n \times d

                   d = \frac{\text{Optical path length through benzene}}{2 \times n}

                       = \frac{\lambda}{2 \times n}  

                       = \frac{615 \times 10^{-9}}{2 \times 1.501}   (as 1 nm = 10^{-9}m

                       = 204.9 m          

Thus, we can conclude that minimum thickness of benzene is 204.9 m.

4 0
3 years ago
Which is the correct Lewis structure of C2H4
Maslowich
Lewis structure for C2H4

3 0
3 years ago
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