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ad-work [718]
3 years ago
13

If an object is not moving, it has no

Chemistry
2 answers:
marishachu [46]3 years ago
7 0

Answer:

b

Explanation:

Tanzania [10]3 years ago
5 0

Answer:

that answer is B

Explanation:

the answer is b luv

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The average atomic mass for any element will be closest to the average atomic mass of the ________ isotope.
dezoksy [38]

Answer:

Explanation:

The average atomic mass for any element will be closest to the average atomic mass of the __different______ isotopes.

To calculate the average atomic mass of any element, the mass spectrometry method helps to determine the proportion/percentage/fraction by which each of the isotopes of an element occurs in nature. The proportion is called the geonormal abundance or abundance. From this, the average atomic mass of an element from different isotopes can be calculated.

5 0
3 years ago
Which of the following accurately describes the pH scale? 
aleksandrvk [35]
The correct answer is <span>B. The greater the pH is, the lower the acidity is.</span>
6 0
3 years ago
Read 2 more answers
Which of the following of Dalton's theories do we no longer use today?
allsm [11]
We no longer use atoms of the same elements are identical in size, mass and properties.
5 0
4 years ago
A chemist titrates 90.0 mL of a 0.5870 M acetic acid (HCH, CO) solution with 0.4794M NaOH solution at 25 °C. Calculate the pH at
hjlf

Answer:

9.09

Explanation:

Please kindly check attachment for the step by step solution of the given problem.

8 0
3 years ago
What is the pH of a 0.28 M solution of ascorbic acid (Vitamin C)? (The values for Ka1 and Ka2 for ascorbic acid are 8.0×10−5 and
Tomtit [17]

Answer:

pH = 2.32

Explanation:

H2A + H2O -------> H3O+ + HA-    

Ka2 is very less so i am not considering that dissociation.

now Ka = 8.0×10−5

            = [H3O+] [HA-] / [H2A]

lets concentration of H3O+ = X then above equation will be

8.0×10−5 = [X] [X] / [0.28 -X]

8.0×10−5 = X2 /  [0.28 -X]

X2 + 8.0×10−5 X - 2.24 x 10−5

solve the quardratic equation

X =0.004693 M

pH = -log[H+}

    = -log [0.004693]

    = 2.3285

    ≅2.32

pH = 2.32

5 0
3 years ago
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