We are going to do this step by step:
Let's start with option A
A.
X = 25 and Y = 5/2
![y=\frac{2}{5}\cdot x=\frac{2}{5}\cdot25=\frac{2\cdot25}{5}=\frac{50}{5}=\frac{5\cdot10}{5\cdot1}=10](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B2%7D%7B5%7D%5Ccdot%20x%3D%5Cfrac%7B2%7D%7B5%7D%5Ccdot25%3D%5Cfrac%7B2%5Ccdot25%7D%7B5%7D%3D%5Cfrac%7B50%7D%7B5%7D%3D%5Cfrac%7B5%5Ccdot10%7D%7B5%5Ccdot1%7D%3D10)
In this case, when X = 25 , then Y = 10 ,which is different to 5/2
B.
X = 14 , Y = 35
![y=\frac{2}{5}\cdot14=\frac{28}{5}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B2%7D%7B5%7D%5Ccdot14%3D%5Cfrac%7B28%7D%7B5%7D)
In case, when X = 14, then Y = 28/5, which is different to 35
C.
X = 40 , Y = 24
![y=\frac{2}{5}\cdot40=\frac{80}{5}=16](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B2%7D%7B5%7D%5Ccdot40%3D%5Cfrac%7B80%7D%7B5%7D%3D16)
Similarly, in this case, when X = 40, then Y = 16, which is different to 24
D.
X = 10 , Y=4
![y=\frac{2}{5}\cdot10=\frac{20}{5}=4](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B2%7D%7B5%7D%5Ccdot10%3D%5Cfrac%7B20%7D%7B5%7D%3D4)
Now, in this case, we can see that when X = 10, then Y = 4 which is the same as the given value of Y
E.
X = 50 , Y = 20
![y=\frac{2}{5}\cdot50=\frac{100}{5}=20](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B2%7D%7B5%7D%5Ccdot50%3D%5Cfrac%7B100%7D%7B5%7D%3D20)
In this case, the values of Y are also the same.
F.
X = 30 , Y = 12
![y=\frac{2}{5}\cdot30=\frac{60}{5}=12](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B2%7D%7B5%7D%5Ccdot30%3D%5Cfrac%7B60%7D%7B5%7D%3D12)
Again, in this case, the values of Y are the same, so the pair satisfies the equation.
In conclusion: options D, E and F satisfy the equation