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OLEGan [10]
3 years ago
7

Arrange the compounds by their reactivity toward electrophilic aromatic substitution.

Chemistry
1 answer:
swat323 years ago
4 0

Answer:

The order of reactivity towards electrophilic susbtitution is shown below:

a. anisole > ethylbenzene>benzene>chlorobenzene>nitrobenzene

b. p-cresol>p-xylene>toluene>benzene

c.Phenol>propylbenzene>benzene>benzoic acid

d.p-chloromethylbenzene>p-methylnitrobenzene> 2-chloro-1-methyl-4-nitrobenzene> 1-methyl-2,4-dinitrobenzene

Explanation:

Electron donating groups favor the electrophilic substitution reactions at ortho and para positions of the benzene ring.

For example: -OH, -OCH3, -NH2, Alkyl groups favor electrophilic aromatic substitution in benzene.

The -I (negative inductive effect) groups, electron-withdrawing groups deactivate the benzene ring towards electrophilic aromatic substitution.

Examples: -NO2, -SO3H, halide groups, Carboxylic acid groups, carbonyl gropus.

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What is the atomic number of the as yet undiscovered element in which the 8s and 8p electron energy levels?
Andreyy89

The atomic number of the undiscovered element is 168

Element 118 will have just filled its 7p orbitals. therefore the predicted element to fill completely up to its 8 p orbital would have to filled a whole set of s, p, d, f and g orbitals

That's another 2 + 6 + 10 +14 + 18 = 50 electrons

To determine the total number of quantum numbers we have to find

Nml × Nms

we have Nml × Nms = ( 2 + 1 ) × 2

8s + 8P + 7d + 6f + 5g = 2 + 6 + 10 + 14 + 18 = 50

The element right below should be

Z = 118 + 50

   = 168

Hence the atomic number of the undiscovered element is 168

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How many grams of solute are needed to prepare a 3.50% mass/mass solution that has a solution mass of 2.50x102 grams.
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A certain substance X has a normal freezing point of -6.4 C and a molal freezing point depression constant Kf= 3.96 degrees C.kg
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Answer:  1.0\times 10^2g

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=(-6.4-(13.6))^0C=7.2^0C = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte like urea)

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m= molality

\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}}\times \text{weight of solvent in kg}}

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Mass of non electrolyte (urea) added = ?

7.2=1\times 3.96\times \frac{xg}{60.06 g/mol\times 0.95kg}

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Thus 1.0\times 10^2g urea was dissolved.

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3 years ago
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