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masha68 [24]
3 years ago
15

How many total atoms in 3CuSO4

Chemistry
2 answers:
Nikolay [14]3 years ago
7 0

Answer:

8

Explanation:

Step2247 [10]3 years ago
5 0

Answer:

18

Explanation:

Element   Symbol   no of Atoms

Copper           Cu                3

Sulfur            S                3

Oxygen           O                  12

                                              18 = total

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A positively charged particle is placed next to an negatively charged object. In which direction does the positively charged par
Arte-miy333 [17]

Answer:

The positively charged particle will go towards the negatively charged particle because opposites attract.

Explanation:

4 0
4 years ago
Cans someone help me lol ;)<br> WILL MARK BRAINLIEST!!
lidiya [134]

Answer:

The answer to your question is:

Explanation:

1.- Noble gases are special because they do not react, they are stable because they have 8 electrons in their outermost shell.

2.- Hellium

    Neon

    Argon

    Krypton

    Xenon

    Radon

3.- Magnesium

    Calcium

4.- Magnesium

5.- VII A Halogen

6.- III A, IVA, VA, VIA

7.- Nitrogen

8.-                              Categories of the periodic table

Metals                                 Metalloids                            Non-metals

Group IA and IIA                Groups IIIA to VIA                Groups IVA to VIIA

Groups B's

9.- Left side

10.- right side

11.- non metal / left

3 0
3 years ago
Find the boiling point temperature at 760 torr of an isomer of octane, c8h18, if its enthalpy of vaporization is 38,210 j mol-1
mixas84 [53]

According to Clausius-Clayperon equation,

ln(\frac{P_{1} }{P_{2} }) = \frac{delta H_{vap} }{R} (\frac{1}{T_{2} }-\frac{1}{T_{1} }   )

P_{1}is the vapor pressure at boiling point = 760 torr

P_{2} is the vapor pressure at T_{2} =638.43 torr

TemperatureT_{2} = 110.0^{0}C + 273 = 383 K

ΔH_{vap} = 38210 J/mol

Plugging in the values, we get

ln(\frac{P_{1} }{P_{2} }) = \frac{delta H_{vap} }{R} (\frac{1}{T_{2} }-\frac{1}{T_{1} }   )

ln\frac{760 torr}{638.43 torr} =\frac{38210 J/mol}{8.314 J/(mol.K)} (\frac{1}{383 K}-\frac{1}{T_{1} }

T_{1} = 389 K

Therefore, the boiling point of octane = 389 K - 273 = 116^{0}C

7 0
3 years ago
An air sample consists of oxygen and nitrogen gas as major components. It also contains carbon dioxide and traces of some rare g
jekas [21]

Explanation:

A mixture is defined as the substance that contains two or more different number of substances that are physically mixed together.

For example, a mixture of air which contains oxygen, nitrogen and other gases.

A mixture in which solute particles are unevenly distributed into the solvent then it is known as a heterogeneous mixture.

For example, sand in water is a heterogeneous mixture.

A homogeneous mixture is defined as the mixture in which solute particles are evenly distributed in a solvent.

A homogeneous mixture is a clear solution.

For example, salt dissolved in water is a homogeneous mixture.

A solution is defined as the substance in which two or more substances are mixed together.

A compound is defined as the substance that contains two or more different elements that chemically combined together in a fixed ratio by mass.

A element is defined as the substance that contains only one type of atoms.

For example, a piece of sodium element will contain only atoms of sodium.

Whereas a pure substance is defined as the substance which contains only one type of molecule or one type of atom.

For example, O_{2}, N_{2} etc are pure substances.

Thus, we can conclude that the terms which could be used to describe the given sample of air is as follows.

  • pure chemical substance.
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  • mixture.
4 0
3 years ago
An isotope has a half-life of 10 minutes. after 20 minutes, what percentage of the original nuclei remain?
Elena-2011 [213]
To solve this, we can use two equations.
t1/2 = ln 2 / λ = 0.693 / λ  
   
where, t1/2 is half-life and λ is the decay constant.

t1/2 = 10 min = 0.693 / λ

Hence, λ = 0.693 / 10 min              -         (1)

Nt = Nο e∧(-λt)    
                
Nt = amount of atoms at t =t time
Nο= initial amount of atoms
t = time taken

by rearranging the equation,
Nt/Nο = e∧(-λt)                  -  (2)

From (1) and (2),

Nt/Nο = e∧(-(0.693 / 10 min) x 20 min) 
Nt/Nο = 0.2500

Percentage of remaining nuclei = (nuclei at t time / initial nuclei) x 100%
                                                     
= (Nt/Nο ) x 100%
                                                      = 0.2500 x 100%
                                                      = 25.00%

Hence, Percentage of remaining nuclei is 25.00%
6 0
3 years ago
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