Answer:
compared to the incident angle, the refracted angle is 45.56⁰
Explanation:
From Snell's law;
n₁sin(I) = n₂sin(r)
Where;
n₁ is the refractive index of light in medium 1 = 1.2
n₂ is the refractive index of light in medium 2 = 1.4
I is the incident angle
r is the refractive angle

I = 56.439⁰
Applying snell's law

Therefore, compared to the incident angle, the refracted angle is 45.56⁰
I believe it’s force but i’m not really sure.
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