Question

A uniform magnetic field B=5.210 T is perpendicular to the plane of the paper (into the page). The current-carrying wire of value I = 2.000A (directed to the right) with length L=0.5000m perpendicular to the magnetic field and current is going from left to right. Find the magnitude of the magnetic force (in Tesla) on the wire. A. 5.210T
B. 10.42T
C. 0T
D. Can not be determined
Please show work!

Answer 1

Answer:5.21 N

Explanation:

Given

B=5.210 T

I=2 A

L=0.5 m

Given Wire is perpendicular to Magnetic field

$\theta =90^{\circ}$

$F=IL\times B$

$F=BIL sin\theta$

$F=5.210\cdot 2\cdot 0.5 sin(90)$

F=5.210 N

as  1 Tesla =1 N/A/m