How is the molar mass of a molecule determined? What are its units?

What is a hypothesis?

raketka [301]

An explanation or answer based on the facts or evidence you have.

5 0

3 years ago

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The three types of nuclear radiation in increasing order of penetrating power are ____.

cricket20 [7]

Answer:

The three types of nuclear radiation in increasing order of penetrating power are ____.

alpha, beta, gamma

Explanation:

Alpha Ray: This has the least penetrating power because the particles produced during decay are large in quantity but they have a very low energy which dosent alow them to move far through space because the are ususally blocked.

Beta ray : they have more penetrating power than alpha rays because they a bit higher in energy and quantity {size}

Gamma Ray; this has the most penetrating power. they are highly powerful waves but do little at ionization of other atoms or molecules. it penetrates through molecules very easily due to its size and energy.

5 0

3 years ago

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What is the differentences between atomic number and atomic mass?

natima [27]

Atomic number is number on periodic table, mass is how big element is

3 0

3 years ago

Consider the relationship (y+3)2 = b/(x-2), where y and x are variables and bis a constant. On rectangular coordinate paper, wha

Nikolay [14]

Answer:

(-1) is the slope of a graph of In(y+3) on the vertical axis versus In(x-2) on the horizontal axis.

Explanation:

$\frac{(y+3)}{2} = \frac{b}{(x-2)}$

Taking natural logarithm on both the sides:

$\ln [(y+3)]-\ln[2]=\ln [b]-\ln [(x-2)]$

$\ln [(y+3)]=\ln[2]+\ln [b]-\ln [(x-2)]$

$\ln [(y+3)]=\ln {[2\times b]-\ln [(x-2)]$

Slope intercept form is generally given as:

$y=mx+c$

m = slope, c = intercept on y axis or vertical axis

On rearranging equation:

$\ln [(y+3)]=(-1)\times \ln [(x-2)]+\ln {2b}$

y = ln [(y+3)], x = ln [(x-2)], m=-1 , c = ln 2b

(-1) is the slope of a graph of In(y+3) on the vertical axis versus In(x-2) on the horizontal axis.

8 0

3 years ago

Calculate the change in the entropy of the system and also the change in the entropy of the surroundings, and the resulting tota

Ghella [55]

Answer:

(a) Δ $S_{sys}$ = 2.881 J/K; Δ $S_{sur}$ = -2.881 J/K; total change in entropy = 0

(b)Δ $S_{sys}$ = 2.881 J/K; Δ $S_{sur}$ = 0 ; total change in entropy = 2.881 J/K

(c) Δ $S_{sys}$ = 0 ; Δ $S_{sur}$ = 0 ; total change in entropy = 0

Explanation:

In the given problem, we need to calculate the change in the entropy of the system and also the change in the entropy of the surroundings, and the resulting total change in entropy, when a sample of nitrogen gas of mass 14 g at 298 K and 1.00 bar doubles its volume. We have the following variable:

mass (m) = 14 g

Temperature = 298 K

Pressure = 1.00 bar

Initial volume = $V_{1}$

Final volume = $V_{2}$ = $2V_{1}$

(a) Change in entropy of the system Δ $S_{sys}$ = $nRIn\frac{V_{2} }{V_{1} }$

where R = 8.314 J/(mol*K)

n = number of moles = mass/molar mass = 14/ 28 = 0.5 moles

Δ $S_{sys}$ = 0.5*8.314*ln2 = 2.881 J/K

Change in entropy of the surrounding Δ $S_{sur}$ = -2.881 J/K

Therefore, for a reversible process, the total change in entropy = Δ $S_{sys}$ +Δ $S_{sur}$ = 2.881 - 2.881 = 0

(b) Because entropy is a state function, we use the same procedure as in part (a). Thus, Δ $S_{sys}$ = 2.881 J/K

Since surrounding does not change in this process Δ $S_{sur}$ = 0.

total change in entropy = Δ $S_{sys}$ +Δ $S_{sur}$ = 2.881 - 0 = 2.88 J/K

(c) For an adiabatic reversible expansion, q(rev) = 0, thus:

Δ $S_{sys}$ = 0

Since heat energy is not transferred from the system to the surrounding

Δ $S_{sur}$ = 0

total change in entropy = Δ $S_{sys}$ +Δ $S_{sur}$ = 0

6 0

3 years ago