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Vladimir [108]
3 years ago
15

Which reaction below requires the greatest amount of amount of oxygen per mole of explosive for complete oxidation (combustion)

to CO2 and H2O.
a. CH3OH
b.CH2=CHCH3
c. CH Ξ CH
d. No right answer.
Chemistry
1 answer:
andriy [413]3 years ago
5 0

Answer:

The answer to your question is: letter B

Explanation:

First, write the reactions and balance them

a.             2 CH3OH   +  3 O2     ⇒   2  CO2    +   4 H2O

                 ratio   3/2 = 1.5

b.            2 CH2 = CHCH3 +  9 O2  ⇒  3 CO2   + 3 H2O

                 ratio     9/2 = 4.5

c.            2 CH ≡ CH    +   5 O2   ⇒  4 CO2   + 2 H2O

                 ratio     5/2 = 2.5

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12 times breathe give 240 ml of pure O_{2}. Each breathe gives 20 ml of O_{2}.

Let us consider, volume of air per breathe= x ml.

Pure O_{2} from inhaled air= \frac{20}{100}x ml and Pure O_{2} from exhaled air= \frac{16}{100}x ml.

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So, \frac{20}{100}x + \frac{16}{100}x = 20

Therefore, x = 55.5 ml

So, volume of air per breath= 55.5 ml.


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