Neither of those questions makes sense, and I believe that you should not waste your time worrying about them.
#61 gives you a lot of information about a ball, and then asks a question about a glove.
#62 gives a mysterious equation, doesn't tell you what either of the variables represents, and then asks for a quantity without ever telling us how that quantity is related to the equation.
Personally, my response to both questions would be "Insufficient information given".
The answer is false. many famouse scientist used the very scientific theory that we use today
1) 24500 J (29400 J if we include also the water)
The gravitational potential energy of an object is given by:
where m is the mass, g is the gravitational acceleration and h is the heigth above the ground.
Therefore, the gravitational potential energy of the cylinder is given by:
If we count also the water inside the cylinder, the total mass is 5.0 kg + 1.0 kg = 6.0 kg, and the total gravitational potential energy would be
2) 24530 J
The heat energy added to the water is given by:
where
m = 1.0 kg is the mass of the water
C = 4186 J/kg C is the specific heat of the water
is the increase in temperature
Substituing, we find
3) 1.0 kg
The mass of the water is given, and it is m = 1.0 kg.
4)
The temperature change of the water is the difference between its final temperature and its initial temperature:
5)
The specific heat of the water is
Answer:
The period of that same pendulum on the moon is 12.0 seconds.
Explanation:
To determine the period of that same pendulum on the moon,
First, we will determine the value of g (which is a measure of the strength of Earth's gravity) on the Moon. Let the value of g on the Moon be .
From the question, the strength of earth’s gravity is only 1/6th of the normal value. The normal value of g is 9.8 m/s²
∴ =
= 1.63 m/s²
From the question, T=2π√L/g
We can write that,
.......... (1)
Where is the period of the pendulum on Earth and is the measure of the strength of Earth's gravity
and
.......... (2)
Where is the period of the pendulum on Moon and is the measure of the strength of Earth's gravity on the Moon.
Since we are to determine the period of the same pendulum on the moon, then, and are constants.
Dividing equation (1) by (2), we get
From the question,
= 9.8 m/s²
= 1.63 m/s²
= ??
From,
∴
Hence, the period of that same pendulum on the moon is 12.0 seconds.
Its 30 kg cause I got 30 kg dude.