Ask question

Ask question

All categories

2 years ago

11

a scoop of baking soda is added to a beaker containing vinager.the baking soda disapears and bubbles are observed.this is an exa

mple of an change

1 answer:

icang [17]2 years ago

5 0

The change happening here is called a chemical change. ^-^

You might be interested in

what type of orbital is occupied by an electron with the quantum numbers n=3, 1=2? How many degenerate orbital's of this type ar

ki77a [65]

Tryna boost my score for college chemistry could you give me the brainiest and a thanks? Hope you find your answer your looking for!

4 0

3 years ago

Chemists use activity series to determine whether which type of reaction will occur?

ruslelena [56]

Single replacement reactions. For example copper is more reactive than silver. So a copper wire in a silver solution will cause the silver to become a metal again.

5 0

3 years ago

Read 2 more answers

Bob measured out 1.60 grams of sodium. He calculates that 1.60 g of

saul85 [17]

Answer:

84.8%

Explanation:

Step 1: Given data

Bob measured out 1.60 g of Na. He forms NaCl according to the following equation.

Na + 1/2 Cl₂ ⇒ NaCl

According to this equation, he calculates that 1.60 g of sodium should produce 4.07 g of NaCl, which is the theoretical yield. However, he carries out the experiment and only makes 3.45 g of NaCl, which is the real yield.

Step 2: Calculate the percent yield.

We will use the following expression.

%yield = real yield / theoretical yield × 100%

%yield = 3.45 g / 4.07 g × 100% = 84.8%

6 0

3 years ago

What is the difference in energy between an electron in 1s and an electron in 4s.

Andre45 [30]

Answer:

Explanation:

An electron in 4s is farther away from nucleus and it has higher energy when compared to electron from 1s.

5 0

3 years ago

10 points!! Please give me work with it and I will mark as brainlist.

Georgia [21]

Answer: The molecular formula will be $C_2H_4O_2$

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C = 40.0 g

Mass of O = 53.3 g

Mass of H = 6.66 g

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{40.0g}{12g/mole}=3.33moles$

Moles of O = $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{53.3g}{16g/mole}=3.33moles$

Moles of H = $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{6.66g}{1g/mole}=6.66moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{3.33}{3.33}=1$

For O = $\frac{3.33}{3.33}=1$

For H = $\frac{6.66}{3.33}=2$

The ratio of C : O : H = 1: 1: 2

Hence the empirical formula is $COH_2$

The empirical weight of $COH_2$ = 1(12)+1(16)+2(1)= 30g.

The molecular weight = 60 g/mole

Now we have to calculate the molecular formula.

$n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{60}{30}=2$

The molecular formula will be= $2\times CH_2O=C_2H_4O_2$

8 0

2 years ago