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Anna35 [415]
3 years ago
7

Reduction is a reaction which results in a __1____ in electrons and a __2____ in positive charge of the atom or ion

Chemistry
1 answer:
mestny [16]3 years ago
7 0

Hello! Your answer would be a gain of electrons and a decrease in positive charge.

Contrary to how it sounds, reduction is actually a gain of electrons. It is part of a set of reactions known as a redox reaction, reduction being a gain of electrons and oxidation being a loss.

With the gain of electrons, the element would become more negative as electrons bring with them a negative charge. Therefore, this would decrease the positive charge.

Hope this helped!

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A sample of gas has an initial volume of 3.62 L at a pressure of 0.987 atm. If the volume of the gas decreases to 2.50 L, what w
statuscvo [17]

Answer:

0.033 atm

Explanation:

PV=nRT

rule of 1 for T and n

P= nRT/V

P= 1(.08206)1)/ 2.50

0.033 atm = pressure

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Identify the reaction type and the products. Al+F2 ->
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2 years ago
What is the ratio of [a–]/[ha] at ph 2.75? the pka of formic acid (methanoic acid, h–cooh) is 3.75?
Varvara68 [4.7K]

The dissociation of formic acid is:

HCOOH \rightleftharpoons HCOO^{-} + H^{+}

The acid dissociation constant of formic acid, k_a is:

k_a = \frac{[HCOO^{-}]  [H^{+}]}{HCOOH}

Rearranging the equation:

\frac{[HCOO^{-}]}{[HCOOH]} = \frac{k_a}{[H_+]}

pH = 2.75

pH = -log[H^{+}]

[H^{+}]= 10^{-2.75} = 1.78 \times 10^{-3}

pk_a = 3.75

k_a = 10^{-3.75} = 1.78\times 10^{-4}

Substituting the values in the equation:

\frac{[HCOO^{-}]}{[HCOOH]} = \frac{k_a}{[H_+]}

\frac{[HCOO^{-}]}{[HCOOH]} = \frac{1.78\times 10^{-4}}{1.78\times 10^{-3}}

Hence, the ratio is \frac{1}{10}.

4 0
3 years ago
Which of the following is not a weakness of the Rutherford model of the atom?
Harrizon [31]
The answer to this is t<span>he atom is mostly empty space.</span>
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If you made a three-dimensional model of an atom and its nucleus, how would you represent the atom? 7th grade
Gemiola [76]

Answer:

it shows the breakdown of the atom

Explanation:

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7 0
3 years ago
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