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Anna35 [415]
4 years ago
7

Reduction is a reaction which results in a __1____ in electrons and a __2____ in positive charge of the atom or ion

Chemistry
1 answer:
mestny [16]4 years ago
7 0

Hello! Your answer would be a gain of electrons and a decrease in positive charge.

Contrary to how it sounds, reduction is actually a gain of electrons. It is part of a set of reactions known as a redox reaction, reduction being a gain of electrons and oxidation being a loss.

With the gain of electrons, the element would become more negative as electrons bring with them a negative charge. Therefore, this would decrease the positive charge.

Hope this helped!

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E=mc (square) E= mass times capacity squared
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3 years ago
What do chemists use percent yield calculations for in the real world?
STALIN [3.7K]

Answer:

C. To determine how efficient reactions are.

D. To determine how much reactant they need.

Explanation:

When you are doing a reaction, you are hoping for a percent yield to close of 100%. You make the reaction and determine how many product you obtain. If you know the percent yield of a reaction you can calculate the amount of reactant you need to obtain a determined amount of product.

Having this in mind:

A. To balance the reaction equation.  false. To calculate percent yield you need to balance the reaction before. You don't use percent yield to balance the reaction

B. To determine how much product they will need.  false. You determine how much product you obtain after the reaction. How much product you need is independent of percent yield

C. To determine how efficient reactions are.  true. A way to determine efficience of a reaction is with percent yield. An efficient reaction has a high percent yield.

D. To determine how much reactant they need. true. If you know percent yield of a reaction you can know how many reactant you must add to obtain  the amount of product you want.

8 0
3 years ago
Consider the arrangement of gases shown below. If the value between the gases is opened and the temperature is held constant, de
goblinko [34]

Answer:

I don't know what to say . just for points

7 0
3 years ago
Pure R,R-hydrobenzoin (side product of meso-hydrobenzoin) has a melting point of 148°C. a) What do you expect the melting point
Alexandra [31]

Answer:

Explanation:

(a) melting point of S,S-hydrobenzoin should be 140°C. Since S,S-hydrobezoin and R,R-hydrobenzoin are enantiomeric pair so that their melting point and boilong point should be same.

(b) different melting point,

Racemic mixture must have different melting point in comparison to the pure enantiomers.

considering a racemic mixture, individual enantiometer possesses a greater affinity for its kind of molecules than for those of the other enantiometer

3 0
3 years ago
Codeine C18H21NO3 is a weak organic base. A 5.0 x 10^-3 M solution of codeine has a pH of 9.95. Calculate the value of Kb for th
arsen [322]

Answer:

Kb = 4.45\times10^{-7}\ mol/L

p^{Kb}=6.35

Explanation:

For a weak organic base, the formula to find p^{OH} is given by:

p^{OH}=p^{K_b}+\log c

where c is the concentration of base.

Here c= 5\times10^{-3}\ M

p^{H}=9.95\\p^{OH}=14-p^{H}=14-9.95=4.05

Substituting the above values in the formula,we get:

p^{k_b}=p^{OH}-\log c\\p^{k_b}=4.05-\log (5\times10^{-3})\\p^{K_b}=6.35\\K_b=$antilog 6.35=4.45\times10^{-7}\ mol/L

Hence:

Kb = 4.45\times10^{-7}\ mol/L

p^{Kb}=6.35

7 0
3 years ago
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