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White raven [17]
2 years ago
9

Which statement is true about molecule speed? (1 point)

Chemistry
1 answer:
ANTONII [103]2 years ago
8 0

Faster molecules have fewer collisions than slower molecules is True about molecular speed.

<h3>What is Molecular speed?</h3>

Molecular speed refers to the average distance gases or molecules travelled atca particular time rate.

It is valid in ideal gas, where the molecules do not interact with others.

Average molecular speed = Square root (3 (ideal gas constant) * (Temperature)/m)

Therefore, Faster molecules have fewer collisions than slower molecules is True about molecular speed.

Learn more about molecular speed from the link below.

brainly.com/question/14327643

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Help with chemistry hw
Free_Kalibri [48]
The answer is 2.138 g of H2
8 0
3 years ago
Phosphorus pentachloride decomposes to phosphorus trichloride at high temperatures according to the equation:
weqwewe [10]

Answer:

D) [PCl5]=0.00765M,[PCl3]=0.117M,and [Cl2]=0.0.117M

Explanation:

Based on the reaction:

PCl₅(g) ⇄ PCl₃(g) + Cl₂(g)

And knowing:

Kc = [PCl₃] [Cl₂] / [PCl₅] = 1.80

When you add PCl₅ into a flask, this gas will react producing PCl₃ and Cl₂ until [PCl₃] [Cl₂] / [PCl₅] = 1.80

This could be written as:

[PCl₃] = X

[Cl₂] = X

[PCl₅] = 0.125M - X

<em>Where X represents the moles of PCl₅ that react, </em><em>reaction coordinate.</em>

Replacing in Kc expression:

[PCl₃] [Cl₂] / [PCl₅] = 1.80

[X [X] / [0.125 - X] = 1.80

X² = 0.225 - 1.80X

0 = -X² -1.80X + 0.225

Solving for X:

X = -1.9M → False solution, there is no negative concentrations

X = 0.11735M → Right solution.

Replacing, concentrations in equilibrium are:

[PCl₃] = X

[Cl₂] = X

[PCl₅] = 0.125M - X

[PCl₃] = 0.117M

[Cl₂] = 0.117M

[PCl₅] = 0.00765M

And right option is:

<h3>D) [PCl5]=0.00765M,[PCl3]=0.117M,and [Cl2]=0.0.117M</h3>
7 0
3 years ago
Nitrogen and hydrogen combine to form ammonia in the Haber process. Calculate (in kJ) the standard enthalpy change ∆H° for the r
Kazeer [188]

Answer:

∆H° rxn = - 93 kJ

Explanation:

Recall that a change in standard in enthalpy, ∆H°, can be calculated from the inventory of the energies, H, of the bonds  broken minus bonds formed (H according to Hess Law.

We need to find in an appropiate reference table the bond energies for all the species in the reactions and then compute the result.

              N₂ (g)   +            3H₂ (g)   ⇒                          2NH₃ (g)

1 N≡N = 1(945 kJ/mol)     3 H-H = 3 (432 kJ/mol)       6 N-H = 6 ( 389 kJ/mol)

∆H° rxn = ∑  H bonds broken  - ∑ H bonds formed

∆H° rxn = [ 1(945 kJ)   + 3 (432 kJ) ] - [ 6 (389 k J]

∆H° rxn = 2,241 kJ -2334 kJ = -93 kJ

be careful when reading values from the reference table since you will find listed N-N bond energy (single bond), but we have instead a triple bond,  N≡N,  we have to use this one .

8 0
3 years ago
The electron configuration of Ne is:
Slav-nsk [51]

I think it is correct......

3 0
4 years ago
Which of the following is true about a carbonated soft drink?
Makovka662 [10]
I would say the water is the solvent and carbon dioxide is the solute. Carbon dioxide is usually introduced to water under pressure and then sealed. Once the cap is removed, the carbon dioxide starts to escape since it is then under low pressure. Sometimes, natural groundwater has dissolved carbon dioxide in it but most of our soft drinks have it artificially introduced. Water plus carbon dioxide also form carbonic acid and this can give the tingly sensation on the tongue when drinking soft drinks.
4 0
3 years ago
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