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nirvana33 [79]
3 years ago
14

Stream Piracy – Kaaterskill, NY. Check and double-click the Problem 15 folder. The dark blue and orange streams highlight the pr

ocess of stream piracy/stream capture (i.e., they are pirating/capturing the headwaters of the cyan and magenta streams, respectively). Which of the following helps promote this?
a. The pirating streams are larger and can hold more water than the other streams.
b. The pirating streams are eroding headwardly to intersect more of the other streams’ drainage basins, causing water to be diverted down their steeper gradients.
c. The land to the west is being uplifted.
d. Landslides have diverted the water into the stream pirates.
Engineering
1 answer:
baherus [9]3 years ago
5 0

Answer:

b. The pirating streams are eroding headwardly to intersect more of the other streams’ drainage basins, causing water to be diverted down their steeper gradients.

Explanation:

From the Kaaterskill NY 15 minute map (1906), this shows two classic examples of stream capture.

The Kaaterskill Creek flow down the east relatively steep slopes into the Hudson River Valley. While, the Gooseberry Creek is a low gradient stream flowing down the west direction which in turn drains the higher parts of the Catskills in this area.

However, there is Headward erosion of Kaaterskill Creek which resulted to the capture of part of the headwaters of Gooseberry Creek.

The evidence for this is the presence of "barbed" (enters at obtuse rather than acute angle) tributary which enters Kaaterskill Creek from South Lake which was once a part of the Gooseberry Creek drainage system.

It should be noted again, that there is drainage divide between the Gooseberry and Kaaterskill drainage systems (just to the left of the word Twilight) which is located in the center of the valley.

As it progresses, this divide will then move westward as Kaaterskill captures more and more of the Gooseberry system.

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Consider a piston-cylinder device with a piston surface area of 0.1 m^2 initially filled with 0.05 m^3 of saturated water vapor
miv72 [106K]

The friction force f = 10000 N

The heat transfer Q = 1.7936 KJ

<u>Explanation:</u>

Given data:

Surface area of Piston = 1 m^{2}

Volume of saturated water vapor = 100 K Pa

Steam volume = 0.05 m^{3}

Using the table of steam at 100 K pa

Steam density = 0.590 Kg/m^{3}

Specific heat C_{p} = 2.0267 KJ/Kg K

Mass of vapor = S × V

m = 0.590 × 0.05

m = 0.0295 Kg

Solution:

a) The friction force is calculated

Friction force = In the given situation, the force need to stuck the piston.

= pressure inside the cylinder × piston area

= 100 × 10^{3}  × 0.1

f = 10000 N

b)  To calculate heat transfer.

Heat transfer = Heat needs drop temperatures 30°C.

Q=m c_{p} \ DT

Q = 0.0295 × 2.0267 × 10^{3} × 30

Q = 1.7936 KJ

3 0
3 years ago
Problem 1 (10 points) In the first homework you were instructed to design the mechanical components of an oscillating compact di
Ilya [14]

Answer:

Problem 1 (10 points) In the first homework you were instructed to design the mechanical components of an oscillating compact disc reader. Since you did such a good job in your design, the company decided to work with you in their latest Blue-ray readers, as well. However, this time the task is that once the user hits eject button, the motor that spins the disc slows down from 2000 rpm to 300 rpm and at 300 rpm a passive torsional spring-damper mechanism engages to decelerate and stop the disc. Here, your task is to design this spring-damper system such that the disc comes to rest without any oscillations. The rotational inertia of the disc (J) is 2.5 x 10-5kg m² and the torsional spring constant (k) is 5 × 10¬³NM. Calculate the critical damping coefficient cc for the system. choice of the damper, bear in mind that a good engineer stays at least a factor of In your 2 away from the danger zone (i.e., oscillations in this case). Use the Runge Kutta method to simulate the time dependent angular position of the disc, using the value of damping coefficient (c) that calculated. you Figure 1: Blue-ray disc and torsional spring-damper system.

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3 years ago
A levee will be constructed to provide some flood protection for a residential area. The residences are willing to accept a one-
777dan777 [17]

Answer:

1709.07 ft^3/s

Explanation:

Annual peak streamflow = Log10(Q [ft^3/s] )

mean = 1.835

standard deviation = 0.65

Probability of levee been overtopped in the next 15 years = 1/5

<u>Determine the design flow ins ft^3/s </u>

P₁₅ = 1 - ( q )^15 = 1 - ( 1 - 1/T )^15 = 0.2

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Q₁₅ = 1 - 0.2 = 0.8

Applying Lognormal distribution : Zt = mean + ( K₂ * std ) --- ( 1 )

K₂ = 2.054 + ( 67.72 - 50 ) / ( 100 - 50 ) * ( 2.326 - 2.054 )

    = 2.1504

back to equation 1

Zt = 1.835 + ( 2.1504 * 0.65 )  = 3.23276

hence:

Log₁₀ ( Qt(ft^3/s) ) = Zt  = 3.23276

hence ; Qt = 10^3.23276

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4 0
3 years ago
Benzoic acid 1.35 g, is reacted with oxygen in a constant volumecalorimeter to form H2 O(l) and CO2 (g)at 298 K. the mass of the
brilliants [131]

Answer:

Explanation:C7H6O2 + (15/2) O2 = > 3H2O + 7CO2 delH = Σ stoichiometric coefficient* enthalpy of formation delH = (7*-393.509 kJ/mol) + (3*-285.83 kJ/mol) - (15/2 * 0) -(1*-385.2 kJ/mol) delH = -3226.853 kJ/mol benzoic acid ...

6 0
3 years ago
A quantity of nitrogen gas in a piston–cylinder assembly undergoes a process at a constant pressureof 80 bar from 220 to 300 K.
notka56 [123]

Answer:

work done =  665.12 kJ/k.mol  of nitrogen  

dQ = 685.905 kJ/k.mol of nitrogen

Explanation:

given data

pressure = 80 bar

temperature t1  = 220 K

temperature t2 =   300 K

solution

first we get here work done as considering ideal gas condition

work done = P (v2-v1 )   = nR (t2-t1)    

put here value

work done = 1 × 8.314 ×( 300 - 220 )

work done =  665.12 kJ/k.mol  of nitrogen  

and

now we get heat transfer by 1st law of thermodynamics that is

heat transfer dQ = dv + dw

dQ = Cv dT + dw

put here value and we get

dQ =  \frac{R}{\gamma -1 }   × (t2-t1) + 665.12

dQ = \frac{8.314}{1.4-1}  × (300-220) + 665.12

dQ = 685.905 kJ/k.mol of nitrogen

8 0
3 years ago
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