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3 years ago

Explain how the colors of the visible light spectrum are organized using the terms wavelength and frequency.

Chemistry

1 answer:

Eddi Din [679]3 years ago

3 0

Answer:

Visible light spectrum is a part of electromagnetic waves. The colors of the visible light spectrum are organised on the basis of their wavelength and frequency.

As the light or color having high frequency will have the shorter wavelength and vice versa, so colors in visible light spectrum arranged from highest frequency to lowest frequency or from shortest wavelength to highest wavelength. For example: The highest frequency color is violet and lowest frequency of visible light is red.

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I have a chemistry question that I am needing help on please?

aliina [53]

What country and grade are you?
Please tell me! I’m going to help you

8 0

3 years ago

Two gas-containers, A and B, are connected with a valve. The first container, A, has a volume of 135 mL, and the second containe

stiv31 [10]

Answer:

85.5 mmHg is the pressure of the gas sample when the valve is opened.

Explanation:

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas in container A = 165 mmHg

$P_2$ = final pressure of gas = ?

$V_1$ = initial volume of gas in container A= $135 mL$

$V_2$ = final volume of gas = 135 mL + 117 mL = 252 mL

$T_1$ = initial temperature of gas in container A = $22.5^oC=273+22.5=295.5 K$

$T_2$ = final temperature of gas = $12.7^oC=273+12.7=285.7K$

Now put all the given values in the above equation, we get:

$P_2=\frac{P_1V_1\times T_2}{T_1\times V_2}$

$=\frac{165 mmHg\times 135 mL\times 285.7 K}{295.5 K\times 252 mL}$

$P_2=85.5 mmHg$

85.5 mmHg is the pressure of the gas sample when the valve is opened.

8 0

4 years ago

Is a ph = 7.25 solution acidic, basic, or neutral at 0 Â°c?

Ilya [14]

Answer is: solution is acidic, because pH value is less than 7,46.
The Kw (the ionic product for water) at 0°C is 0,12·10⁻¹⁴ mol²/dm⁶.
Kw = [H⁺] · [OH⁻<span>].
</span>[H⁺] = [OH⁻] = √0,12·10⁻¹⁴ mol²/dm⁶.
[H⁺] = [OH⁻] = 3,5·10⁻⁸ mol/L.
pH = -log[H⁺].
pH = -log(3,5·10⁻⁸ mol/L).
pH = 7,46; neutral solution on 0°C.

4 0

4 years ago

The common titanium alloy known as T-64 has a composition of 90 weight% titanium 6 wt% aluminum and 4 wt% vanadium. Calculate th

Anna007 [38]

Explanation:

Suppose in 100 g of alloy contains 90% titanium 6% aluminum and 4% vanadium.

Mass of titanium = 90 g

Moles of titanium = $\frac{90 g}{47.87 g/mol}=1.8800 mol$