Step 1 : write a valanced equation..
NaOH + HCl 》NaCl + H2O
Step 2 : find the number of mole of HCl..
1000 ml ..contains 4.3 mole
15ml... (4.3÷1000)×15 =...
Stem 3 : use mole ratio....
HCl : NaOH
1 : 1
So mole is same as calculated above...
Step 4 :
3.5 mole of NaOH is in 1000ml
(4.3÷1000)×15 mole is in ....
Do the calculation
"Sigma"s between the hydrogens and the oxygen
Mercury is a chemical element with the symbol Hg and atomic number 80. The electron configuration of Hg is 6s2 4f14 5d10.
<h3>
How to write an electronic configuration?</h3>
1. Identify the given element and its atomic number from the periodic table.
2. Write the electron configuration by the energy level and the type of orbital first, then the number of electrons present in the orbital as superscript.
The easiest way to write the electronic configuration for any element is by using a diagonal rule for electron filling order in the different subshells according to the Aufbau principle.
The 3 rules for writing the electron configuration in the orbital box diagram are – the Aufbau rule, the Pauli-exclusion rule, and Hund's Rule.
To learn more about electronic configuration, refer
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Answer:
2.5 L will be the volume of HNO₃
Explanation:
To find out the total volume of nitric acid in liters we begin from molarity.
HNO₃ solution is 0.10 M
This means that 0.10 moles are contained in 1L of solution.
As we used 0.25 moles of nitric, let's determine the volume by a rule of three:
0.10 moles of nitric acid are contained in 1L of solution
0.25 moles of nitric acid will be contained in (0.25 . 1) / 0.1 = 2.5 L
Answer:
<h2>1.264 × 10²⁴ molecules</h2>
Explanation:
The number of molecules can be found by using the formula
N = n × L
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
N = 2.10 × 6.02 × 10²³
We have the final answer as
<h3>1.264 × 10²⁴ molecules</h3>
Hope this helps you