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Leona [35]
3 years ago
12

- Unit 1 Worksheet 4

Chemistry
1 answer:
3241004551 [841]3 years ago
4 0
I think it is C or F
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From the combinations of substances listed below, which would most likely be miscible in
polet [3.4K]

Answer:

C

Explanation:

polar has unequal sharing of electrons that has the lone pairs which has the electronegativity difference. can be mixed with water.

4 0
3 years ago
How do trends in the periodic table help predict the properties of an element
irina1246 [14]
As you move around there is a change in: electronegativies, ionisation energies, atomic radius etc. different amounts of these properties are going to effect how the element acts
8 0
2 years ago
How many half-lives are required for the concentration of reactant to decrease to 1.56% of its original value?4247.56.56
neonofarm [45]

Answer:

6 half-lives are required for the concentration of reactant to decrease to 1.56% of its original value.

Explanation:

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,

[A_t] is the concentration at time t

[A_0] is the initial concentration

Given:

Concentration is decreased to 1.56 % which means that 0.0156 of [A_0] is decomposed. So,

\frac {[A_t]}{[A_0]} = 0.0156

Thus,

\frac {[A_t]}{[A_0]}=e^{-k\times t}

0.0156=e^{-k\times t}

kt = 4.1604

The expression for the half life is:-

Half life = 15.0 hours

t_{1/2}=\frac {ln\ 2}{k}

Where, k is rate constant

So,  

k=\frac {ln\ 2}{t_{1/2}}

\frac{4.1604}{t}=\frac {ln\ 2}{t_{1/2}}

t = 6\times t_{1/2}

<u>6 half-lives are required for the concentration of reactant to decrease to 1.56% of its original value.</u>

6 0
3 years ago
Menthol (FW = 156.3 g/mol), the strong-smelling substance in many cough drops, is a compound of carbon, hydrogen, and oxygen. Wh
Alisiya [41]

Answer: the molecular formula is C10H20O

Explanation:Please see attachment for explanation

7 0
3 years ago
What is the volume of a sample if the density is 2.35 g/mL and the mass is 33.67 g?
lawyer [7]
  • Density=2.35g/mL
  • Mass=33.67g

\\ \star\sf\longmapsto Density=\dfrac{Mass}{Volume}

\\ \star\sf\longmapsto Volume=\dfrac{Mass}{Density}

\\ \star\sf\longmapsto Volume=\dfrac{33.67}{2.35}

\\ \star\sf\longmapsto Volume=14.32mL

6 0
2 years ago
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