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olga55 [171]
3 years ago
15

The residents of a city voted on whether to raise property taxes. The ratio of yes votes to no votes was 5 to 3 . If there were

4395 total votes, how many yes votes were there?
Mathematics
1 answer:
Alchen [17]3 years ago
7 0

Answer:

There were 2747 yes votes.

Step-by-step explanation:

This question can be solved using proportions.

The ratio of yes votes to no votes was 5 to 3 .

This means that for each 5 + 3 = 8 votes, 5 were yes and 3 were no.

If there were 4395 total votes, how many yes votes were there?

For each 8 votes, we have 5 yes. How many yes votes were there in 4395 votes?

5 yes - 8 votes

x yes - 4395 votes

8x = 4395*5

x = 4395*5/8

x = 2747

There were 2747 yes votes.

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Who made an error? <br> The correct scale factor= ?
Ostrovityanka [42]

Answer:

reggie made an error

the correct scale factor is 2/3

Step-by-step explanation:

we want to get from A to A', B to B', and ultimately C to C'

to get there, we must multiply each value in each point by the scale factor.

let's start out with reggie's scale factor. he multiplies each value in C by 3/2 to get to C'. we can try this out with one point, e.g. A

for A: 3/2 * (-12, -6) = (-18, -9). this is not A' = (-8, -4)! thus, 3/2 cannot be the scale factor

now, onto hillary's scale factor of 2/3

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the correct scale factor is thus hillary's: 2/3

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2 years ago
Four horses are pulling a wagon. Each horse drinks 45000 ml of water each day. How many liters of water will the horses drink in
s2008m [1.1K]

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3 years ago
How many solutions do these equations have
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Answer:

\large\boxed{\bold{one\ solution}\ (1,\ -4)\to x=1,\ y=-4}

Step-by-step explanation:

\left\{\begin{array}{ccc}y=2x-6\\y=-x-3\end{array}\right\\\\\text{These are linear functions. We only need two points to draw a graph.}\\\\\text{Choice two values of x, substitute to the equation,}\\\text{and calculate the values of y.}\\\\y=2x-6\\for\ x=0\to y=2(0)-6=0-6=-6\to(0,\ -6)\\for\ x=3\to y=2(3)-6=6-6=0\to(3,\ 0)\\\\y=-x-3\\for\ x=0\to y=-0-3=0-3=-3\to(0,\ -3)\\for\ x=-3\to y=-(-3)-3=3-3=0\to(-3,\ 0)\\\\\text{Look at the picture}

\text{The intersection of the line is the solution of the system of equations:}\\\\(1,\ -4)\to x=1,\ y=-4

7 0
3 years ago
X^2+4x-1/(x+2)^2=0 solve for x
dalvyx [7]
<span>x^2+4x-1/(x+2)^2=0
x^2 + 4x - 1 = 0
</span>
\frac{x^2+10x-7}{x^2+10x+25} =0\\x^2+10x-7=0\\x= \frac{-b\pm\sqrt{b^2-4ac}}{2a};
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x=\frac{-4\pm\sqrt{4^2-(4\times1\times(-1)}}{2\times1}\\=\frac{-4\pm\sqrt{16+4}}{2}=\frac{-4\pm\sqrt{20}}{2}\\=\frac{-4\pm\sqrt{4\times5}}{2}=\frac{-4\pm2\sqrt{5}}{2}=-2\pm\sqrt{5}\\=-2+\sqrt{5}&#10; \ or \ -2-\sqrt{5}\\x=0.24 \ or \ x = -4.24
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2 years ago
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