Answer:
Explanation:
since force is applied downwards at some angle with the horizontal
so here we will have
now we know that the box will not move if applied force is balanced by frictional force on it
so we will have
so here we can say
Easy question lol
2 answers:
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Answer:
The velocity of the launcher after the projectile is launched is -5.011 m/s
Explanation:
Here we have the mass of the cannon and cart, m₁ = 4.65 kg
Velocity of cannon and cart, v₁ = 2.00 m/s
Mass of projectile, m₂ = 50.0 g = 0.05 kg
Velocity of projectile, v₂ = 647 m/s
Velocity of the launcher, v₃ = Required
Mass of cannon and cart, launcher after launching projectile m₃ = 4.65-0.05
= 4.6 kg
Therefore, from the principle of the conservation of linear momentum, we have
Total initial momentum = Total final momentum
m₁ × v₁ = m₂ × v₂ + m₃ × v₃
Substituting gives
4.65 kg × 2.00 m/s = 0.05 kg × 647 m/s + 4.6 kg × v₃
4.65 kg × 2.00 m/s - 0.05 kg × 647 m/s = 4.6 kg × v₃
-23.05 kg·m/s = 4.6 kg × v₃
v₃ = -5.011 m/s.