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Lana71 [14]
3 years ago
14

Answer them all please!!

Physics
1 answer:
liubo4ka [24]3 years ago
6 0

Answer:

1. stomach

2. arteries

3. trachea

4. spinal cord

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Which safety procedure should you follow after breaking a mercury thermometer?
agasfer [191]
B. move away from the mercury and notify the teacher :)

you should never use a broom to sweep mercury, it breaks the mercury in smaller droplets and spread them.
Pouring the mercury in the sink would likely be logged in the plumbing. and pickingthings up with the napkin may cause contamination and cuts from the glass.
3 0
3 years ago
GIVING 94 POINTS!!!!!! PLS HELP MEH
pishuonlain [190]

Answer:

A) asteroid

Explanation:

3 0
3 years ago
A mass on the end of a spring undergoes simple harmonic motion. At the instant when the mass is at its equilibrium position, wha
Paha777 [63]

Answer:

3.At equilibrium, its instantaneous velocity is at maximum

Explanation:

The motion of a mass on the end of a spring is a simple harmonic motion. In a simple harmonic motion, the total mechanical energy of the system is constant, and it is sum of the elastic potential energy (U) and the kinetic energy of the mass (K):

E=U+K=\frac{1}{2}kx^2+\frac{1}{2}mv^2 = const.

where

k is the spring constant

x is the displacement of the spring from equilibrium

m is the mass

v is the speed

As we see from the formula, since the total energy E is constant, when the displacement (x) increases, the speed (v) increases, and viceversa. Therefore, when the mass is at its equilibrium position (which corresponds to x=0), the velocity of the mass will be maximum.

7 0
3 years ago
In a lab, the mass of object A is 2.5 kg. Object A weighs:
dangina [55]

Answer:

25N

Explanation:

Assuming the lab is on earth:

w = mg = 2.5 (9.81) = 25N

8 0
3 years ago
Frequency of the wave below?
agasfer [191]

It's hard to tell exactly what's happening in that 110 cm that you marked over the wave. What is under the ends of the long arrow ? How many complete waves ? I counted 4.5 complete waves ... maybe ?

If there are 4.5 complete waves in 110cm, then the length of 1 wave is (110/4.5)=24.44cm.

Frequency = speed/wavelength

Frequency = 2m/s /0.2444m

Frequency = 8.18 Hz

6 0
3 years ago
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