Plz helpppppppppppppppppppppppppppppppppppp

A motorist traveled 250 miles on 11 gallons of gas. With the same vehicle, about how far could he go on 16 gallons of gas? A) 17

Andrei [34K]

ANSWER

$363.6 \: miles$
EXPLANATION

We were told that the motorist travelled 250 miles on 11 gallons of gas. This implies that,

$250 \: miles \equiv11 \: gallons$

Now we want to find how far he could go on 16 gallons.

$x \: miles \equiv16 \: gallons$

All other things being equal, the motorist should cover more than 250 miles with 16 gallons of gas.

Recall that: If more, less divides.

This implies that,

$x = \frac{250 \times 16}{11}$

$x = \frac{4000}{11} = 363.6 \: miles$

Therefore the correct answer is C.

3 0

3 years ago

Help pleaseeee!!!!!!

kaheart [24]

Communitive Property of Addition

4 0

2 years ago

• A researcher claims that less than 40% of U.S. cell phone owners use their phone for most of their online browsing. In a rando

antiseptic1488 [7]

Answer:

We failed to reject H₀

Z > -1.645

-1.84 > -1.645

We failed to reject H₀

p > α

0.03 > 0.01

We do not have significant evidence at a 1% significance level to claim that less than 40% of U.S. cell phone owners use their phones for most of their online browsing.

Step-by-step explanation:

Set up hypotheses:

Null hypotheses = H₀: p = 0.40

Alternate hypotheses = H₁: p < 0.40

Determine the level of significance and Z-score:

Given level of significance = 1% = 0.01

Since it is a lower tailed test,

Z-score = -2.33 (lower tailed)

Determine type of test:

Since the alternate hypothesis states that less than 40% of U.S. cell phone owners use their phone for most of their online browsing, therefore we will use a lower tailed test.

Select the test statistic:

Since the sample size is quite large (n > 30) therefore, we will use Z-distribution.

Set up decision rule:

Since it is a lower tailed test, using a Z statistic at a significance level of 1%

We Reject H₀ if Z < -1.645

We Reject H₀ if p ≤ α

Compute the test statistic:

$Z = \frac{\hat{p} - p}{ \sqrt{\frac{p(1-p)}{n} }}$

$Z = \frac{0.31 - 0.40}{ \sqrt{\frac{0.40(1-0.40)}{100} }}$

$Z = \frac{- 0.09}{ 0.048989 }$

$Z = - 1.84$

From the z-table, the p-value corresponding to the test statistic -1.84 is

p = 0.03288

Conclusion:

We failed to reject H₀

Z > -1.645

-1.84 > -1.645

We failed to reject H₀

p > α

0.03 > 0.01

We do not have significant evidence at a 1% significance level to claim that less than 40% of U.S. cell phone owners use their phones for most of their online browsing.

8 0

3 years ago

What is the value of x?

Vaselesa [24]

In a right triangle, the hypotenuse is √2 x the legs. In this case, the value of x is $\frac{18}{\sqrt{2} } =\frac{18\sqrt{2} }{2} =9\sqrt{2}$ .