Please help me with question A and B pleaseeeeee

2 and 3 i need help with. look at the attatched picture

snow_lady [41]

Answer:

2. +7

Explanation:

The oxidation state of Cl in `HClO_(4)` is +7.Apr 17, 2022

3ans. CrS+2No3 --) 2No+So4+cr^3+

Cr=1 Cr=1

S=1 S=1

N=1=2 N=1=2

O=3=6 o=5=6

now that is how it look and it is not balanced in oxygen so add 2 in the front of No3.

it will look something like this 2NO3. even if u add 2 in the fornt it is not balance so add again 2 in the No in second and it will look like this 2NO.

so now it is blance.

6 0

2 years ago

What data should be plotted to show that experimental concentration data fits a first-order reaction? A) 1/[reactant] vs. time B

natita [175]

Answer:

C) In[reactant] vs. time

Explanation:

For a first order reaction the integrated rate law equation is:

$A = A_{0}e^{-kt}$

where A(0) = initial concentration of the reactant

A = concentration after time 't'

k = rate constant

Taking ln on both sides gives:

$ln[A] = ln[A]_{0}-kt$

Therefore a plot of ln[A] vs t should give a straight line with a slope = -k

Hence, ln[reactant] vs time should be plotted for a first order reaction.

7 0

4 years ago

For a molecule of hydrazoic acid (HN3, also known as hydrogen azide), the atoms are arranged as HNNN. One resonance form of HN3

disa [49]

Answer:

0; +1; -1

Explanation:

The resonance structure of HN₃ is shown below (you can also use horizontal dashes to represent the bonding pairs).

The molecule has 16 valence electrons, and each N atom has an octet.

To get the formal charges, cut the covalent bonds in half.

Each atom gets the electrons on its side of the cut.

Formal charge = valence electrons in isolated atom - electrons on bonded atom

FC = VE - BE

(a) On Nₐ

VE = 5

BE = 1 lone pair (2)+ 3 bonding electrons = 2 + 3 = 5

FC = 5 - 5 = 0.

(b) On Nb:

VE = 5

BE = 4 bonding electrons = 4

FC = 5 - 4 = +1

(c) On Nc:

VE = 6

BE = 2 lone pairs(4) + 2 bonding electrons = 4 + 2 = 6

FC = 5 - 6 = -1

7 0

3 years ago

Osmotic pressure Π is given by the relation:Π = iMRTwhere i is the van’t Hoff factor, M is the concentration of solute, R is the

lions [1.4K]

<u>Answer:</u> The concentration of solute is 0.503 mol/L

<u>Explanation:</u>

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

$\pi=icRT$

where,

$\pi$ = osmotic pressure of the solution = 24 atm

i = Van't hoff factor = 2 (for NaCl)

c = concentration of solute = ?

R = Gas constant = $0.08\text{ L atm }mol^{-1}K^{-1}$

T = temperature of the solution = $25^oC=[273+25]=298K$

Putting values in above equation, we get:

$24atm=2\times c\times 0.08\text{ L.atm }mol^{-1}K^{-1}\times 298K\\\\c=0.503mol/L$

Hence, the concentration of solute is 0.503 mol/L

5 0

3 years ago

Which element in the 18th column of the periodic table has the largest radius?

aivan3 [116]

Radon. As you move down a group in the periodic table you essentially add new energy levels to the one above it, making the atom larger.

6 0

3 years ago