Explanation:
First, find the velocity of the projectile needed to reach a height h when fired straight up.
Given:
Δy = h
v = 0
a = -g
Find: v₀
v² = v₀² + 2aΔy
(0)² = v₀² + 2(-g)(h)
v₀ = √(2gh)
Now find the height reached if the projectile is launched at a 45° angle.
Given:
v₀ = √(2gh) sin 45° = √(2gh) / √2 = √(gh)
v = 0
a = -g
Find: Δy
v² = v₀² + 2aΔy
(0)² = √(gh)² + 2(-g)Δy
2gΔy = gh
Δy = h/2
Answer:
Please check the explanation.
Explanation:
The slope of the velocity-time graph illustrates the change in velocity with respect to change in time.
In other words, the acceleration of the object is defined by the slope of a velocity graph. The acceleration can be obtained by finding the slope at a particular time.
Hence, the slope of the velocity time graph represent represents acceleration.
2. Also the acceleration of any object, like a car or bike, at some discrete instant in time 't' is termed as instantaneous acceleration which can be determined if we may take the derivate of the given velocity function.
3. A vector that has a direction and magnitude of 1 is termed as a unit vector, often called a direction vector.
The oxygen has more electronegativity (3.44), making hydrogen more 'positive'. Hydrogen will be attracted to Cl since it is more 'negative'. Electronegativity(EN) of H is 2.2 whereas Cl has EN of 3.16
The centripetal force exerted on the automobile while rounding the curve is 
<u>Explanation:</u>
given that

Objects moving around a circular track will experience centripetal force towards the center of the circular track.
