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3 years ago

7. What is the kinetic energy of a 3-kilogram ball that is rolling at 2 meters per second?

Physics

2 answers:

Alexus [3.1K]3 years ago

5 0

Answer:

6 Joules

Explanation:

KE= ½ m v2 = ½ (3kg) (2 m/s)2 = 6 Joules 8.

vitfil [10]3 years ago

3 0

Answer:

6Newton meter is the answer.

Explanation:

Mass=m=3kg

Velocity=v=2m/s

Kinetic energy =K.E.=?

As we know that

K.E.=1/2mv^2

Putting the values

K.E.=1/2✖️3kg✖️(2m/s)^2

K.E.=1/2✖️3kg✖️4m^2/s^2

K.E=1/2✖️12Nm

K.E.=6Nm is your answer

Hope it will help you :)

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Convert an acceleration of 12m/s^2 to km/h^2

ozzi

Answer:

43.2

because to convert from m/sec to kmph we need to multiply by 3600/1000

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3 years ago

A hiker is at the bottom of a canyon facing the canyon wall closest to her. She is 280.5 meters from the wall and the sound of h

ValentinkaMS [17]

Answer:

4.80 seconds

Explanation:

The velocity of sound is obtained from;

V= 2d/t

Where;

V= velocity of sound = 329.2 ms-1

d= distance from the wall = 790.5 m

t= time = the unknown

t= 2d/V

t= 2 × 790.5/ 329.2

t= 4.80 seconds

8 0

3 years ago

A wind generator, such as the one shown , uses the power of wind to generate electricity What do you think is happening inside t

sesenic [268]

Answer:

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8 0

3 years ago

Read 2 more answers

A submarine is 2.84 102 m horizontally from shore and 1.00 102 m beneath the surface of the water. A laser beam is sent from the

xxMikexx [17]

Answer:

468 m

Explanation:

So the building and the point where the laser hit the water surface make a right triangle. Let's call this triangle ABC where A is at the base of the building, B is at the top of the building, and C is where the laser hits the water surface. Similarly, the submarine, the projected submarine on the surface and the point where the laser hit the surface makes a another right triangle CDE. Let D be the submarine and E is the other point.

The length CE is length AE - length AC = 284 - 234 = 50 m

We can calculate the angle ECD:

$tan(\hat{ECD}) = \frac{ED}{EC} = \frac{100}{50} = 2$