Answer: k = 5.4kg/m
where m is the mass of the crate.
Explanation:
The force of kinetic friction is described by the equation:
Ff = k*N
in the opposite direction in wich the object moves, where k is the coefficient of kinetic friction and N is the normal force, that is equal to the weight of the crate. N = m*g where m is the mass of the crate and g is the gravitational acceleration.
If the crate keeps moving with constant velocity, this means that the crate is not accelerating so there is no net force applied on the crate. Then the friction force should be equal in magnitude to the horizontal force of 53N (but with different sign)
then we have:
k*m*g = 53N
k*m = 53N/9.8m/s^2 = 5.4kg
k = 5.4kg/m
In the question we do not have the mass of the crate, so you must put the value in that equation to get the value of k.
The answer is D, all responses are correct
Answer:
30hz is the answer for the question
Answer:
Nodes = 5 and antinodes = 4
Explanation:
Nodes are the points of zero amplitude and appear to be fixed. On the other hand, antinodes are points on a stationary wave that oscillates with maximum amplitude.
In this given standing wave, there are 5 points where the amplitude is 0. So, there are 5 nodes. Also, there are 4 points where the amplitude is maximum.
So, there are 5 nodes and 4 antinodes.
Answer:
C) No work is required to move the negative charge from point A to point B.
Explanation:
An equipotential surface is defined as a surface connecting all the points at the same potential.
Therefore, when a charge moves along an equipotential surface, it moves between points at same potential.
The work done when moving a charge is given by
where
q is the charge
is the potential difference between the initial and final point of motion of the charge
However, the charge in this problem moves along an equipotential surface: this means that the potential does not change, so
And so, the work done is also zero.
