What is the centripetal acceleration of a small laboratory centrifuge in which the tip of the test tube is moving at 19.0 meters

Question

2 years ago

11

/second in a circle with a radius of 10.0 centimeters?

2 answers:

Volgvan · Answer 1 · 2022-07-08T22:46:46+03:00

Volgvan2 years ago

7 0

A_central = v^2/r = (19)^2/10 = 36.1 m/s^2

vivado [14] · Answer 2 · 2022-07-09T00:03:57+03:00

7 0

First convert the centimeters to meters which is 0.01m then using the equation centripital acceleration= v^2 / r = 19^2 / 0.01 you get 36100m/s^2