What is the centripetal acceleration of a small laboratory centrifuge in which the tip of the test tube is moving at 19.0 meters
/second in a circle with a radius of 10.0 centimeters?
2 answers:
A_central = v^2/r = (19)^2/10 = 36.1 m/s^2
First convert the centimeters to meters which is 0.01m then using the equation centripital acceleration= v^2 / r = 19^2 / 0.01 you get 36100m/s^2
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