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Whitepunk [10]
3 years ago
11

What is the centripetal acceleration of a small laboratory centrifuge in which the tip of the test tube is moving at 19.0 meters

/second in a circle with a radius of 10.0 centimeters?
Physics
2 answers:
Volgvan3 years ago
7 0
A_central = v^2/r = (19)^2/10 = 36.1 m/s^2
vivado [14]3 years ago
7 0

First convert the centimeters to meters which is 0.01m then using the equation centripital acceleration= v^2 / r = 19^2 / 0.01 you get 36100m/s^2

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3 years ago
1. Driving at slower speeds than traffic flow _____________ .
r-ruslan [8.4K]

<u>The correct option is (D). The strength of electric field depends on the amount of charge that produces the field as well as the distance from the charge. </u>

<u> </u>

Further Explanation:

The electric field intensity at a point is the measure of the force exerted by a charge particle on another charge particle in the particular area of its strength.

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The above expression of electric field shows that the electric field intensity at a point depends on the amount of charge as well as the distance of the point from the charge.

<u>Thus, the correct option is (D). The strength of electric field depends on the amount of charge that produces the field as well as the distance from the charge. </u>

<u> </u>

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Answer Details:

Grade: Senior school

Subject: Physics

Chapter: Electrostatics

Keywords:  Strength, electric field, charge, distance, electric field intensity, magnitude of charge, electrostatic, test charge, kq/r^2.

7 0
3 years ago
Read 2 more answers
PLEASE HELP WILL GIVE 20 POINTS!!!!
Aliun [14]
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at different times.
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This is one complicated combination of many different machines.
I think this is the best choice of description.
6 0
3 years ago
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