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Fynjy0 [20]
3 years ago
8

Find the equation of the line passing through the points (2, 1) and (5, 10).​

Chemistry
1 answer:
Vedmedyk [2.9K]3 years ago
3 0

The equation : y=3x-5

<h3>Further explanation </h3>

Straight-line equations are mathematical equations that are described in the plane of cartesian coordinates

General formula

y-y1 = m(x-x1)

or

y = mx + c

Where

m = straight-line gradient which is the slope of the line

x1, y1 = the Cartesian coordinate that is crossed by the line

c = constant

The formula for a gradient (m) between 2 points in a line

m = Δy / Δx

  • Gradient

\tt \dfrac{10-1}{5-2}=3

  • Equation

\tt y-1=3(x-2)\\\\y-1=3x-6\\\\y=3x-5

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A rectangular block of copper metal weighs 1896 g. The dimensions of the block are 8.4 cm by 5.5 cm by 4.6 cm. From this data, w
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Answer:

Density = 8.92 g/cm³

Explanation:

Density shows the relation of the mass and volume of a determined object. We have this deffinition:

Density = mass / volume

First of all, we calcualte the volume of the block of copper metal, with the data given:

8.4 cm . 5.5 cm . 4.6 cm = 212.52 cm³

Now we replace at the density formula:

Density = 1896 g /212.52 cm³  = 8.92 g/cm³

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4 years ago
What is the atomic mass of one mole of H? g/mole
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650.J is the same amount of energy as? <br>2720cal<br>1550cal<br>650.cal<br>2.72cal
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<u>Ans: 650 J = 155 calories</u>


<u>Given:</u>

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<u>To determine:</u>

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Calculate the percent ionization of nitrous acid in a solution that is 0.230 M in nitrous acid. The acid dissociation constant o
djyliett [7]
Ok first, we have to create a balanced equation for the dissolution of nitrous acid.

HNO2 <-> H(+) + NO2(-)

Next, create an ICE table

           HNO2   <-->  H+        NO2-
[]i        0.230M          0M       0M
Δ[]      -x                   +x         +x
[]f        0.230-x          x           x

Then, using the concentration equation, you get

4.5x10^-4 = [H+][NO2-]/[HNO2]

4.5x10^-4 = x*x / .230 - x

However, because the Ka value for nitrous acid is lower than 10^-3, we can assume the amount it dissociates is negligable, 

assume 0.230-x ≈ 0.230

4.5x10^-4 = x^2/0.230

Then, we solve for x by first multiplying both sides by 0.230 and then taking the square root of both sides.

We get the final concentrations of [H+] and [NO2-] to be x, which equals 0.01M.

Then to find percent dissociation, you do final concentration/initial concentration.

0.01M/0.230M = .0434 or 

≈4.34% dissociation.
8 0
3 years ago
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