Answer:
(a)
(b)
Explanation:
Given:
- Limiting tension of snapping of the rope, T= 387 N
- Weight of the object to be lifted,
- ∴mass,
- height of letting down the weight, h = 6.1 m
(a)
Now,
The force to be compensated for being on the verge of snapping:
(T-w) = 62 N
Therefore, we need to produce and acceleration equivalent to the above force.
∵
(b)
From the equation of motion ,we have:
....................(2)
where:
u= initial velocity= 0 (here, starting from rest)
v= final velocity = ?
s= displacement =h =6.1 m
Now, putting the values in eq. (2)
is the velocity with which the body will hit the ground in the given conditions.