Question

A pitcher throws a ball with a mass of 0.15 kg at a batter with a velocity of 45 m/s towards the batter. The batter exerts a Force of 4500 N opposite the direction of the ball for a time of 0.003 s. What is the velocity of ball coming off the bat?
please if you can do the work i’ll mark you brainliest!!

Answer 1

Answer:

-135m/s

Explanation:

Impulse P=change in momentum

Let the final velocity be -Vf (negative sign due to opposite direction)

Average force =Impulse/Time

=m(-Vf-Vi)/t

=>0.15m.g (-Vf-45)/0.003=4500N

=>0.15 (-Vf-Vi)=13.5

=>(-Vf-Vi)=90

Given,Vi=45

=>(-Vf) =90+45

=>(-Vf)=135

=>Vf = -135m/s

Hope it helps!!!