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Gemiola [76]
2 years ago
13

Psychophysic is the study of

Physics
2 answers:
Morgarella [4.7K]2 years ago
7 0

Answer:

Psychophysics is the subfield of psychology devoted to the study of physical stimuli and their interaction with sensory systems.

Explanation:

Hope this helps <3

lesya [120]2 years ago
5 0
Hope this helps you.

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Molly is jogging on the treadmill. After 20 minutes, her heart rate has not increased, she is able to talk, and she is not sweat
lakkis [162]
Molly could increase her heart rate by turning around and jogging backwards, by jogging on her hands instead of her feet, or by continuing to jog normally but increasing the speed of the treadmill.
3 0
2 years ago
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(NO LINKS) A carpenter strikes a nail with a hammer, pushing it into wood.
Andrej [43]

Answer:

D, Im not very sure about this but I would say D

Explanation:

I tried

6 0
2 years ago
When it is at rotating at full speed, a disk drive in a certain old computer game system revolves once every 0.050 seconds. Star
Gemiola [76]

Answer:

α = 200*π rad/sec²

Explanation:

  • If the disk drive revolves once every 0.05 sec, this means that the angular velocity can be expressed as follows:

        \omega = \frac{2*\pi}{0.05s} = 40*\pi rad/sec

  • (just applying the definition of angular velocity)
  • Now, it the disk started from rest, and took two revolutions to reach to full speed, assuming that the angular acceleration is constant, we can find the angular acceleration applying this kinematic equation:

        \omega_{f} ^{2} -\omega_{0} ^{2} = 2*\alpha * \Delta\theta

  • where Δθ, is the angle rotated while it went from rest to full speed, i.e., 2 revolutions, or 2*π rads.
  • Replacing by the value that we found for ωf (as ω₀ = 0), we  can solve for α :

       \alpha =\frac{\omega_{f}^{2} }{2*\Delta\theta} = \frac{(40*\pi)^{2} }{2*2*2*\pi } =\\ \\ \alpha = 200*\pi rad/sec2

3 0
3 years ago
How much work is accomplished when a force of 300N pushes a box across the floor for a distance of 100 meters?
Nesterboy [21]

So the correct ans is B.

hope it helps u.

5 0
3 years ago
Read 2 more answers
A uniform solid disk of mass 5.00 kg and diameter 47.0 cm starts from rest and rolls without slipping down a 40.0 ∘ incline that
saveliy_v [14]

Answer:

The speed it reaches the bottom is

v=6.51m/s

Explanation:

Given: m=5.0kg, r=47cm\frac{1m}{100cm}=0.47m

Using the conservation of energy theorem

U_i=K_E+K_{ER}

m*g*h=\frac{1}{2}*m*v^2+\frac{1}{2}*I*w^2

v=r*w, I=\frac{1}{2}*m*r^2

m*g*h=\frac{1}{2}*m*(r*w)^2 +\frac{1}{2}*[\frac{1}{2} *m*r^2]*w^2

m*g*h=\frac{3}{4}*m*r^2*w^2

g*h=\frac{3}{4}*r^2*w^2

Solve to w'

w^2=\frac{4*g*h}{3*r^2}

h=x*sin(30)=6.5m*sin(30)=3.25m

w=\sqrt{\frac{4*9.8m/s^2*3.25m}{3*(0.235m)^2}}

w=27.74rad/s

v=27.74rad/s*0.235m=6.51m/s

7 0
3 years ago
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