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3 years ago

The half-life of Cs-137 is 30.2 years. If the initial mass of the sample is 1.00 kg, how much will remain after 151 years?

Physics

2 answers:

nexus9112 [7]3 years ago

8 0

Answer: Its B. There will be 0.031 kg left after 151 years,

Explanation: Im doing my assessment right now.

Xelga [282]3 years ago

3 0

Answer:

i found something on a website that will help you

Explanation:

do you want me to send you it???

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What happens to the density of gas when it compressed

Stella [2.4K]

When a gas is compressed, its particles are pushed closer together so it is more dense.

3 0

3 years ago

A solid, cylindrical wire conductor has radius R = 30 cm. The wire carries a current of 2.0 A which is uniformly distributed ove

blondinia [14]

Answer:

Explanation:

The point at which magnetic field is to be found lies outside wire so while applying Ampere's law we shall take the whole of current . If B be magnetic field which is circular around conductor.

Applying Ampere's law :-

∫ B dl = μ₀ I ; I is current passing through ampere's loop

B x 2π x 2.00 = 4 x π x 10⁻⁷ x 2

B = 2 x 10⁻⁷ T.

7 0

3 years ago

chris and molly wins $2400 in a competition they share the money in the ratio2:3 how much money do they each receive ?

nlexa [21]

Answer:

chris gets 960 and molly gets 1440

Explanation:

add the ratio up and divide

2+3=5

2400/5=480

480x2=960

480x3=1440

960+1440= 2400

5 0

3 years ago

How far from the surface of Earth is the magnitude of Earth's gravitational field equal to 7.86 N/kg?

AfilCa [17]

Answer:

7.48 x 10⁵ m

Explanation:

g = 7.86 N/kg

M = 5.97 x 10²⁴ kg, R = 6.37 x 10⁶ m.

Find height h

g = GM/(R + h)²

(R + h)² = GM/g = 6.67 x 10⁺¹¹ x 5.97 x 10²⁴ /7.86 = 5.066 x 10¹³

R + h = 7.12 x 10⁶ m

h = 7.12 x 10⁶ - 6.37 x 10⁶ = 7.48 x 10⁵ m

4 0

2 years ago

Starting from zero, an electric current is established in a circuit made of a battery of emf E, a resistor of resistance R and a

igor_vitrenko [27]

Answer:

time constant will decrease and steady state current will decrease on increasing the resistance

Explanation:

As we know that the EMF of cell is E which is used to connected across a resistor and an inductor.

So we will have

$E - iR - L\frac{di}{dt} = 0$

here we know that

$i = \frac{E}{R}(1 - e^{-Rt/L})$

now here we have

$\tau = \frac{L}{R}$

so if we increase the value of resistance of the wire then the time constant will decrease

and hence it will take less time to reach near the steady state value

also the steady state current will be smaller in that case

8 0

3 years ago