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Annette [7]
3 years ago
6

6. Why are ionic substances not known as molecules?

Chemistry
2 answers:
Elena L [17]3 years ago
8 0

Answer:

So, an ionic compound actually has two (or even more) different species in a single crystal or solution, which exist independently. The only reason why they are together is because of the total net charge, which must be zero.

Vika [28.1K]3 years ago
5 0

Answer: ionic compounds are not known as molecules because they contain aggregate of positive and negative charges which arise from the transfer of electron from the metallic atom to the non-metallic atom. But in covalent substance, there is a sharing of electron pair between the atoms involved and this makes them to form a molecules

Explanation:

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Generally the ionization potential in a period increases, but there are some exceptions. The one which is not an exception is
Sunny_sXe [5.5K]

Answer:

Generally, the first ionisation energy increases along a period. But there are some exceptions one which is not an exception

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2 years ago
Fe2o3 (s) + 3 co (g) → 2 fe (s) + 3 co2 (g) type of reaction
Mariana [72]
I think is Substitution
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3 years ago
Why the is ratio of magnesium ions to chloride ions in MgCl2 is 1:2?
Monica [59]
You should read up on Proust's law, better known as the Law of Definite Proportions. This is a chemical law that defines your question more generally, on why the ratio of elements and ions are always fixed.

Basically, this compound Magnesium(II) Chloride is MgCl2 because it has the same number of protons, neutrons, and electrons all the way. This defines the properties of the compound or atom. 
5 0
3 years ago
Information-
tekilochka [14]

Answer:

So first thing to do in these types of problems is write out your chemical reaction and balance it:

Mg + O2 --> MgO

Then you need to start thinking about moles of Magnesium for moles of Magnesium Oxide. Based on the above equation 1 mole of Magnesium is needed to make one mole of Magnesium Oxide.

To get moles of magnesium you need to take the grams you started with (.418) and convert to moles by dividing by molecular weight of Mg (24.305), this gives you .0172 moles of Mg.

The theoretical yield would be the assumption that 100% of the magnesium will be converted into Magnesium Oxide, so you would get, based on the first equation, .0172 mol of MgO. Multiplying this by the molecular weight of MgO (24.305+16) gives us .693 g of MgO.

The percent yield is what you actually got in the experiment, and for this you subtract off the total mass from the crucible mass, or 27.374 - 26.687, which gives .66 g of MgO obtained.

Percent yield is acutal/theoretical, .66/.693, or 95.24%.

I'll let you do the same for the second trial, and average percent yield is just an average of the two trials percent yield.

Hope this helps.

6 0
2 years ago
How much water would I need to add to 500 ml of a 2.4 M KCL solution to make a 1.0 M solution
Yuki888 [10]

the answer is 700ml

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