Answer: "donate" hydrogen ions
Explanation:
Mghcl14 + H2 = mghclh 16 work needed to solve this problem
Answer:- Density is 2.54 gram per mL.
Solution:- 
Mass of the marble ball is given as 9.513 g and it's volume is 3.75 mL.
To calculate the density of the marble ball let's plug in the values in the formula:
So, the density of the marble ball is 2.54 gram per mL.
Answer:
the molar mass is 39.997 g/mol
Answer:
T = 100.63 °C
Explanation:
To solve this question, we need to know what are we talking about here. In this case, we want to know the boiling point of a solution with Urea in water. This is a colligative property, so, the expression to use to calculate that is the following:
ΔT = m * K / MM * kg water (1)
Where:
ΔT: difference of temperatures (Tb of solution - Tb water)
m: mass of the urea
K: ebulloscopic constant of the water (0.52 ° C / m)
MM: molecular mass of urea
The boiling point of water is 100 °C, we have the mass of the urea, but not the molar mass. The urea has the formula CH₄N₂O, so the molar mass can be calculated using the atomic mass of the elements (I will use a rounded number for this):
MM = 12 + (4*1) + (2*14) + 16 = 60 g/mol
Now, we can calculate the ΔT and then, the boiling point of the solution:
ΔT = 12 * 0.52 / 60 * 0.165
ΔT = 6.24 / 9.9
ΔT = 0.63 °C
the value of ΔT is a difference between the boling point of water and the solution so:
ΔT = Ts - Tw
Ts = ΔT + Tw
Replacing we have:
Ts = 100 + 0.63
<h2>
Ts = 100.63 ° C</h2>
