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3 years ago

14

What charge does nitrogen form when it satisfies the octet rule?

1 answer:

ExtremeBDS [4]3 years ago

3 0

The answer should be B: -3

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Consider a galvanic (voltaic) cell that has the generic metals X and Y as electrodes. If X is more reactive than Y (that is, X m

amm1812

Answer:

Here's what I get

Explanation:

Assume the metals X and Y are immersed in solutions of XNO₃ and YNO₃ and connected by a salt bridge containing KCl.

$\begin{array}{lcc}\textbf{Item} & \textbf{Apply to X} & \textbf{Apply to Y}\\\text{A. Anode} & \checkmark & \\\text{B. Cathode} & & \checkmark\\\text{C. Electrons toward} & & \checkmark\\\text{D. Electrons from} &\checkmark & \\\text{E. Cations toward} & & \checkmark \\\text{F. Anions toward} &\checkmark & \\\text{G. Gains mass} & & \checkmark\\\text{H. Loses mass} &\checkmark &\\\end{array}$

4 0

3 years ago

5.40 m x 3.21 m x 1.871 m =

mars1129 [50]

The answer would be 32.4m

6 0

3 years ago

If 0.0987 g H2O hydrolyzes, what is the theoretical yield of H2? 2H2O → → 2H2 + O2

Pavlova-9 [17]

The theoretical yield is 0.0110 g H₂.

<em>Moles of H₂O</em> = 0.0987 g H₂O × (1 mol H₂O/18.02 g H₂O) = 0.005 477 mol H₂O

<em>Moles of H₂</em> = 0.005 477 mol H₂O × (2 mol H₂/2 mol H₂O) = 0.005 477 mol H₂

<em>Theoretical yield</em> of H₂ = 0.005 477 mol H₂ × (2.016 g H₂/1 mol H₂)

= 0.0110 g H₂

4 0

3 years ago

Read 2 more answers

The instruction booklet for your pressure cooker indicates that its highest setting is 13.5 psi . You know that standard atmosph

Tom [10]

Answer:

119°C

Explanation:

This question can be solved by using the Clausius-Clayperon Equation.

The formula is given as:

$In(\frac{P_2}{P_1})$ = $(\frac{delta H_{vap}}{R} )$ $(\frac{1}{T_1}-\frac{1}{T_2})$

We can all figured it out that the Heat of vaporization (Δ $H_{vap}$ )= 40.65 kJ/mol or 40,650 J/mol

Now, P₂ (the highest pressure setting) = 14.7 psi + 13.5 psi

=28.2 psi

Also the standard atmospheric pressure (P₁) of $H_2O$ is 14.7 psi (1 atm) and 373K $(T_1)$

∴ substituting our data into the above equation, we have

$In(\frac{28.2 psi}{14,7psi})$ = $(\frac{40650J/mol}{8.314J/mol*k} )(\frac{1}{373}-\frac{1}{T_2} )$

To work out the (In) part in the Left-hand side; we input that directly on the scientific calculator and we have;

0.65 = (4890) $(\frac{1}{373} -\frac{1}{T_2})$

0.65 = $(\frac{1}{3}*4890)-(\frac{1}{T_2}*4890)$

0.65 = 13.1 - $\frac{4890}{T_2}$

0.65 - 13.1 = - $\frac{4890}{T_2}$

-12.45 = - $\frac{4890}{T_2}$

$T_2$ = $(\frac{-4890}{-12.45})$

$T_2$ = 392K

We are tasked with leaving our answer at degree Celsius, therefore 392k to Celsius will be (392-273)°C

= 119°C

3 0

3 years ago

True or false for these!!!! Please help

8090 [49]

False
True
True
False
True
False
Hope this helps!

8 0

3 years ago