If you increase the solute amount but keep the solution volume the same what

Chemistry

1 answer:

solmaris [256]3 years ago

4 0

Answer: Molarity increases

Explanation:

Molarity, also known as concentration in moles/dm3 or g/dm3, is calculated by dividing the amount of solute dissolved by the volume of solvent. So, Molarity (c) = amount of solute (n) / volume (v)

i.e c = n/v

Hence, molarity is directly proportional to the amount of solute dissolved, and inversely proportional to the volume of solvent.

Thus, at same volume, any increase in solute amount increases molarity while a decrease will also decreases molarity.

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Charlotte is driving at 58.6 mi/h and receives a text message. She looks down at her phone and takes her eyes off the road for 4

kramer

Answer: 19.71 feet

Explanation:

Given: Speed of Charlotte =58.6 mi/h

Since 1 hour = 3600 seconds

and 1 mile = 5280 feet

So, Speed of Charlotte = $\dfrac{58.6\times5280}{3600}\approx85.95$ mi/ sec

She looks down at her phone and takes her eyes off the road for 4.36 s.

Since , Distance = $\dfrac{speed}{time}$

So, Distance = $\dfrac{85.95}{4.36}=19.71\ feet$

Hence, Charlotte traveled 19.71 feet during this time.

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3 years ago

Who is interested in a middle schooler?

belka [17]

Answer:

I think that middle school teachers are interested in teaching middle schoolers.

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3 years ago

Natural gas is almost entirely methane. A container with a volume of 2.65L holds 0.120mol of methane. What will the volume be if

mrs_skeptik [129]

The final volume of the methane gas in the container is 6.67 L.

The given parameters;

initial volume of gas in the container, V₁ = 2.65 L
initial number of moles of gas, n₁ = 0.12 mol
additional concentration, n = 0.182 mol

The total number of moles of gas in the container is calculated as follows;

$n_t = 0.12 + 0.182 = 0.302 \ mol$

The final volume of gas in the container is calculated as follows;

$PV = nRT\\\\\frac{V}{n} = \frac{RT}{P} \\\\\frac{V_1}{n_1} = \frac{V_2}{n_2} \\\\V_2 = \frac{V_1 n_2}{n_1} \\\\V_2 = \frac{2.65 \times 0.302}{0.12} \\\\V_2 = 6.67 \ L$