Answer:
Explanation:
Given
mass of steel ball ![m=0.2\ kg](https://tex.z-dn.net/?f=m%3D0.2%5C%20kg)
initial speed of ball ![u=10\ m/s](https://tex.z-dn.net/?f=u%3D10%5C%20m%2Fs)
Final speed of ball
(in upward direction)
Impulse imparted is given by change in the momentum of object
therefore impulse J is given by
![J=\Delta P](https://tex.z-dn.net/?f=J%3D%5CDelta%20P)
![\Delta P=m(v-u)](https://tex.z-dn.net/?f=%5CDelta%20P%3Dm%28v-u%29)
![\Delta P=0.2(-10-10)](https://tex.z-dn.net/?f=%5CDelta%20P%3D0.2%28-10-10%29)
![\Delta =-4\ N-s](https://tex.z-dn.net/?f=%5CDelta%20%3D-4%5C%20N-s)
so magnitude of Impulse =4 N-s
Answer:
False
Explanation:
When the location of the poles changes in the z-plane, the natural or resonant frequency (ω₀) changes which in turn changes the damped frequency (ωd) of the system.
As the poles of a 2nd-order discrete-time system moves away from the origin then natural frequency (ω₀) increases, which in turn increases damped oscillation frequency (ωd) of the system.
ωd = ω₀√(1 - ζ)
Where ζ is called damping ratio.
For small value of ζ
ωd ≈ ω₀
Answer:
B) Power is the rate at which work is done
It creates a white crystal salt MgF2
Resistance can be calculated by Ohm's law
As per ohm's law we will have
![V = i * R](https://tex.z-dn.net/?f=%20V%20%3D%20i%20%2A%20R)
here we will have
voltage = 220 volts
current = 10 A
So by the above formula we will have
![220 = 10* R](https://tex.z-dn.net/?f=220%20%3D%2010%2A%20R)
![R = 22 ohm](https://tex.z-dn.net/?f=R%20%3D%2022%20ohm)
So resistance of the bulb is 22 ohm.