Answer:
23.8 L
Explanation:
There is some info missing. I think this is the original question.
<em>Calculate the volume in liters of a 0.0380M potassium iodide solution that contains 150 g of potassium iodide. Be sure your answer has the correct number of significant digits.</em>
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The molar mass of potassium iodide is 166.00 g/mol. The moles corresponding to 150 grams are:
150 g × (1 mol/166.00 g) = 0.904 mol
0.904 moles of potassium iodide are contained in an unknown volume of a 0.0380 mol/L potassium iodide solution. The volume is:
0.904 mol × (1 L/0.0380 mol) = 23.8 L
We will use this formula for first order:
㏑[A] = - Kt +Ao
when we have t (given)= 30 min = 30 x 60 = 1800 s (we here convert time from min to second.
then we assume that the initial concentration Ao = 1
and the concentration of A (final concentration = 0.25
So by substitution:
㏑(0.25) = - K * 1800 + ㏑(1)
1.39 = K * 1800
∴ K = 0.00077 s^-1 or 7.7 x 10^-4
It is E. because the predators will have slightly more meals with their prey slightly increasing population.
Answer: Option D
Explanation:
Chemotrophs can be defined as the organism which has the ability to get energy by the oxidation of electron donors present in the nearby environments.
These molecules in the environment can be organic or inorganic.These bacteria are usually called as thiobacillus denitrificans.
These bacteria reduce the nitrate into nitrite and the energy source for these bacteria is thiosulfate(sulfur).
