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jarptica [38.1K]
3 years ago
12

Classify the interactions as being direct or indirect competition.

Chemistry
2 answers:
wolverine [178]3 years ago
6 0

I took the same test and got this as my answer and it was right.

spin [16.1K]3 years ago
4 0

Answer:

.-...

Explanation:

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A chemical reaction that produces electricity would be.
Goshia [24]

Answer:

Exothermic

Explanation:

Exothermic describes a process or reaction that releases energy

8 0
2 years ago
In any experiment the accuracy of the data and experiment can be improved. What are some things that can be done to improve data
NARA [144]

Answer:

Conduct more trials.

Add less variables.

Choose a different person

Explanation:

More trials gives plenty of data to be examined.

Less variables makes for less confusion, and less things to keep track of.

Different person ensures that the experiment is not being done by one single person who could be messing up the data

5 0
3 years ago
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Within the context of a person trying to explain why she did well on a psychology exam, an internal attribution is to an externa
Vaselesa [24]
Instinct to learning.

Please vote my answer branliest! Thanks.
5 0
4 years ago
Which of these challenges is unique to the process of designing prostheses as opposed to engineering other technologies?
Nostrana [21]

Answer:

predicting how a tech will interact with human tissue.

Explanation:

thats not really common except for in the medical field.

4 0
2 years ago
If a stock solution of 20.0 g of sugar per 100. ml of solution is available, how much of this stock is needed to prepare 10.0 ml
Vladimir79 [104]

You must use 2.50 mL of the concentrated solution to make 10.0 mL of the dilute solution.

We can use the dilution formula

<em>V</em>_1<em>C</em>_1 = <em>V</em>_2<em>C</em>_2

where

<em>V</em> represents the volumes and

<em>C</em> represents the concentrations

We can rearrange the formula to get

<em>V</em>_2 = <em>V</em>_1 × (<em>C</em>_1/<em>C</em>_2)

<em>V</em>_1 = 10.0 mL; <em>C</em>_1 = 5.00 g/100. mL

<em>V</em>_2 = ?; ____<em>C</em>_2 = 20.0 g/100. mL

∴ <em>V</em>_2 = 10.0 mL × [(5.00 g/100. mL)/(20.0 g/100. mL)] = 10.0 mL × 0.250

= 2.50 mL

3 0
3 years ago
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