Answer:
2730.304 KJ
Explanation:
How much heat is required to convert 0.8 kg of ice at -35°C into steam at 100 C?
Given that:
mass of ice (m) = 0.8 kg = 800 g
Initial temperature () = -35°C = 238 K
final temperature ()= 100°C = 373 K
Specific heat of ice () = 2.108 J/g.K
Specific heat of water () = 4.18 J/g.K
Latent heat of fusion () = 334 J/g.
Latent heat of vaporization () = 2230 J/g.
Total heat (Q) required to increase the temperature of ice from the initial temperature of 238K to final temperature of 373 K is given by the equation:
Answer:
The tension in the cord is 24.1 Newton
Explanation:
<u>Step 1:</u> Data given
mass of the ball = 1.13 kg
Cord = 0.50m
velocity = 2.4 m/s
<u>Step 2:</u> Calculate the tension
Fnet = F(c)
T - F(g) = F(c)
⇒ with F(g) = force of gravity = m*g
⇒ with F(C) = centripetal force = (mv²)/r
T = (mv²)/r + mg
⇒ with m = mass = 1.133 kg
⇒ with v = velocity = 2.4 m/s
⇒ with r = radius = 0.50 m
T = (1.13 * 2.4²) / 0.50 + 1.13 * 9.81
T = 24.1 Newton
The tension in the cord is 24.1 Newton
Answer:
20 miles
Explanation:
Use pythagorean theorem
d^2 = 16^2 + 12^2
to find displacement, d = 20 miles
The bacteria that doesn’t live in extreme conditions is Eubacteria
Yes Flourine is the most active