The length in kilometers of a row of 4.34 x 1023 hydrogen atoms is 4.34 x 10¹⁴ km.
<h3>
Length of the entire hydrogen atoms</h3>
The length of the entire hydrogen atom is calculated as follows;
Length of the row = number x diameter of one
Length of the row = 4.34 x 10²³ x 10⁶ x 10⁻¹²
Length of the row = 4.34 x 10¹⁷ m
Length of the row = 4.34 x 10¹⁴ km
Thus, the length in kilometers of a row of 4.34 x 1023 hydrogen atoms is 4.34 x 10¹⁴ km.
Learn more about diameter of hydrogen atom here: brainly.com/question/13796082
#SPJ1
Answer:
yup that's how you make friends with people on brainly
Answer:
150.0 mL.
Explanation:
- It is known that the no. of millimoles of HNO₃ before dilution = the no. of millimoles of HNO₃ after dilution.
∵ (MV) before dilution = (MV) after dilution.
<em>∴ V before dilution = (MV) after dilution / M before dilution</em> = (0.15 M)(500.0 mL)/(0.50 M) = <em>150.0 mL.</em>
<h2>
→
</h2>
Explanation:
Ethanol can be oxidized to ethanal or acetaldehyde which is further oxidized to acid that is acetic acid.
→ [oxidation by loss of hydrogen]
-
An oxidizing agent potassium dichromate(VI) solution is used to remove the hydrogen from the ethanol.
- An oxidizing agent used along with dilute sulphuric acid for acidification.
Acetaldehyde can also be reduced back to ethanol again by adding hydrogen to it by using a reducing agent that is sodium tetrahydro borate, NaBH4.
- The oxidation of aldehydes to carboxylic acids can be done by the two-step process.
- In the first step, one molecule of water is added in the presence of a catalyst that is acidic.
- There is a generation of a hydrate. (geminal 1,1-diol).
→ 
[reduction by the gain of electrons]
Here, the oxidizing agent used is
in the presence of acetone.
