Answer:
The condor has a wing span of 10 feet
Explanation:
This can be solved by a simple rule of three
In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.
When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too. In this case, the rule of three is a cross multiplication.
When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease. In this case, the rule of three is a line multiplication.
In this problem, our measures are the wing span of the condon in meters and the wing span of the condor is feet. As the value of one of these measures increases, the other is going to increase too.
We know that 1m has 3.281 feet,
So we have the following rule of three:
1m - 3.281 feet
3.05m - x feet
x = 3.821*3.05
x = 10 feet
The condor has a wing span of 10 feet
You should put a picture or finish the question
Answer:
Define the Problem
Background Research
Write a Hypothesis
Carry Out the Experiment
Analyze Data
Draw a Conclusion
Explanation:
First of all, identify the first and last steps before figuring out the middle.
In order, the first and last steps should be
Define the Problem
...
Draw a Conclusion.
Next, you can add your answers in the middle, from beginning to end. That would be,
Define the Problem
Background Research
Write a Hypothesis
Carry Out the Experiment
Analyze Data
Draw a Conclusion
Let me know if this is inaccurate as I am learning everyday. Hope this helped!
The time taken for the same volume of methane gas to diffuse is 7.1 s.
<h3>
Rate of gas diffusion</h3>
The rate at which a given mass of diffuses is inversely proportional to the molar mass of the gas.

where;
- M1 is the molar mass of methane (CH4) = 16 g
- M2 is the molar mass of hydrogen as = 2
- t1 is time taken for methane = 20 s
- t2 is the time taken for hydrogen = ?

Thus, the time taken for the same volume of methane gas to diffuse is 7.1 s.
Learn more about rate of gas diffusion here: brainly.com/question/26696466