Answer:
a.) a = 0 ms⁻²
b.) a = 9.58 ms⁻²
c.) a = 7.67 ms⁻²
Explanation:
a.)
Acceleration (a) is defined as the time rate of change of velocity
Given data
Final velocity = v₂ = 0 m/s
Initial velocity = v ₁ = 0 m/s
As the space shuttle remain at rest for the first 2 minutes i.e there is no change in velocity so,
a = 0 ms⁻²
b.)
Given data
As the space shuttle start from rest, So initial velocity is zero
Initial velocity = v₁ = 0 ms⁻¹
Final velocity = v₂ = 4600 ms⁻¹
Time = t = 8 min = 480 s
By the definition of Acceleration (a)

a = 9.58 ms⁻²
c.)
Given data
As the space shuttle is at rest for first 2 min then start moving, So initial velocity is zero
Initial velocity = v₁ = 0 ms⁻¹
Final velocity = v₂ = 4600 ms⁻¹
Time = t = 10 min = 600 s
By the definition of Acceleration (a)

a = 7.67 ms⁻²
Most likely it would be C not completely sure
The number of protons, electrons, and neutrons in the atom of cr-24 is 28, 24, and 24 respectively.
<h3>What is atom?</h3>
An atom is the smallest unit of matter, consisting of the positively charged nucleus and the electrons which move around it. The atom can not be divided further.
The atom of a matter is made by three elements-
- 1) Neutron-Neutron is the element of an atom, which has zero charge.
- 2) Proton-Proton is the element of an atom, which has a positive charge.
- 3) Electron-Electron is the element of an atom, which has a negative charge.
The atom of cr-24 has the atomic number 24. The atomic number of atom is equal to the number of proton and electron in an atom. Thus,
Now, if this atom has the mass number of 52 (most common). Then the number of neutron is,

Thus, the number of protons, electrons, and neutrons in the atom of cr-24 is 28, 24, and 24 respectively.
Learn more about the atom here;
brainly.com/question/17545314
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The circuit is no longer closed.
Answer:
Steel
Explanation:
Mass is density times volume.
m = ρV
Since they have the same size and shape, they have the same volume.
Steel has a higher density than Styrofoam, so at the same volume, the steel ball will have more mass.